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Hydrogen cyanide, HCN, has a molar mass of 27.03g/mol.
To determine the percent composition of carbon in beryllium cyanide, first find the molar mass of beryllium cyanide, then calculate the molar mass contributed by carbon. Finally, divide the molar mass of carbon by the total molar mass of beryllium cyanide and multiply by 100 to get the percent composition.
The molar mass for anhydrous barium sulfate (BaSO4) is 233.43 g/mol
To determine the mass of barium in barium phosphate, we need to know the molar ratio of barium to oxygen in the compound. If we assume a 1:3 ratio between barium and oxygen in barium phosphate (Ba3(PO4)2), we can calculate the molar mass of barium and oxygen in the compound. With this information, we can find the mass of barium in the sample by subtracting the mass of oxygen from the total mass.
The formula for magnesium cyanide is Mg(CN)2. To find the molar mass, you would add the molar mass of one magnesium atom (24.305 g/mol), and two cyanide ions (26.02 g/mol each). Therefore, the molar mass of magnesium cyanide is 76.345 g/mol.
get the volume of the chemical and the mass and divide the mass by it's volume
The molar mass of BaSO4 (Barium sulfate) can be calculated by adding the molar mass of each element present in the formula: Ba (barium) has a molar mass of 137.33 g/mol, S (sulfur) has a molar mass of 32.06 g/mol, and O (oxygen) has a molar mass of 16.00 g/mol. Adding these together gives a molar mass of 137.33 + 32.06 + (4 * 16.00) = 233.37 g/mol for BaSO4.
The compound with the formula BaCN2 is called barium cyanide. It is composed of barium ions (Ba2+) and cyanide ions (CN-).
233.43 g On A+ the answer's 233.4 =]
CaCl2 = MM(Ca) + 2*MM(Cl) = 40 + 35.5 * 2 =111
To determine the number of moles present, we first need to find the molar mass of barium (Ba), which is approximately 137.33 g/mol. Next, we use the formula n = m/M, where n is the number of moles, m is the mass of the sample (22.3 grams), and M is the molar mass (137.33 g/mol). By substituting these values, we find that there are approximately 0.162 moles of barium in the sample.
The molar mass of barium sulfate, BaSO4 is 233.4 Amount of BaSO4 = mass of sample / molar mass = 14.2/233.4 = 0.0608mol 0.0608 moles of BaSO4 are conained in a 14.2g pure sample.