The mass of 5 mol H2 is 10,08 g.
The mass of 4 mol He is 16,01 g.
5
10g
Mg + 2HCl => MgCl2 + H2 2 moles HCl : 1 mole H2. 2.02 x .5 moles = 1.01 1.01g H2
The mass of 2 moles of H2 gas = 2.00 x 2 = 4.00 g
Given/Known:1mole of H2 = 2.01588g H21mole of H2 = 6.022 x 1023 molecules H21) Convert molecules of H2 to moles of H2 by doing the following calculation.9.4 x 1025 molecules H2 x (1mol H2/6.022 x 1023 molecules H2) = 156mol H22) Convert the moles of H2 to mass in grams of H2.156mol H2 x (2.01588g H2/1mol H2) = 314g H2
2H2 + O2 --> 2H2OFor every 2 moles of H2, 2 moles of H2O will be produced (i.e., a 1:1 ratio). So to produce 8.25 moles of H2O you will also need 8.25 moles of H2
The mass of 2 moles of H2 gas = 2.00 x 2 = 4.00 g
8.086g
Mg + 2HCl => MgCl2 + H2 2 moles HCl : 1 mole H2. 2.02 x .5 moles = 1.01 1.01g H2
Hydrogen gas is H2. 1 moles H2 has a molar mass of 2.0158. Thus, 4 moles H2 gas has a mass of2.0158 g/mole x 4 moles = 8.063 g
The mass of 2 moles of H2 gas = 2.00 x 2 = 4.00 g
Given/Known:1mole of H2 = 2.01588g H21mole of H2 = 6.022 x 1023 molecules H21) Convert molecules of H2 to moles of H2 by doing the following calculation.9.4 x 1025 molecules H2 x (1mol H2/6.022 x 1023 molecules H2) = 156mol H22) Convert the moles of H2 to mass in grams of H2.156mol H2 x (2.01588g H2/1mol H2) = 314g H2
For this you need the atomic (molecular) mass of H2. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.3.00 moles H2 × 2.02 = 6.06 grams H2
Balanced equation first.2H2 + O2 --> 2H2OGet moles products.4 grams H2 (1 mole H2/2.016 grams) = 1.984 moles H264 grams O2 (1 mole O2/32 grams) = 2.000 moles O2I suspect hydrogen gas of limiting and driving the reaction.1.984 moles H2 (1 mole O2/2 moles H2) = 0.992 moles O2 ( you have more than this in equation )2.000 moles O2 (2 mole H2/1 mole O2) = 4.000 moles H2 ( you do not have this much and H2 will drive this reaction )1.984 moles H2 (2 moles H2O/2 moles H2)(18.016 grams/1 mole H2O)= 36 grams water produced====================
2H2 + O2 --> 2H2OFor every 2 moles of H2, 2 moles of H2O will be produced (i.e., a 1:1 ratio). So to produce 8.25 moles of H2O you will also need 8.25 moles of H2
The mass of 2 moles of H2 gas = 2.00 x 2 = 4.00 g
2 moles.
Balanced equation. N2 + 3H2 --> 2NH3 1.4 moles H2 (2 moles NH3/3 moles H2) = 0.93 moles NH3 produced =======================
1. Write the balanced equation: 2Al(s) + 6HCl(aq) ==> 2AlCl3(aq) + 3H2(g)2. Convert 3.70 g Al to moles of Al: 3.70 g x 1 mol/26.98 g 3. Use stoichiometric ratios in balanced equation to find moles H2 produced: answer from step 2 (moles Al) x 3 moles H2/2 moles Al = moles H2 produced 4. Convert moles H2 produced found in step 3 to grams H2 using molar mass of H2