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How many moles of molecules are there in 40.5 g of H2?
To determine the number of moles in 40.5 g of H2, first find the molar mass of H2, which is 2 grams per mole. Next, divide the given mass by the molar mass to find the number of moles. In this case, 40.5 g / 2 g/mol = 20.25 moles of H2.
How many grams of H2 are needed to produce 14.84 g of NH3?
To find the grams of H2 needed, we first calculate the moles of NH3 using its molar mass. Then, we use the balanced chemical equation to determine the mole ratio of H2 to NH3. Finally, we convert moles of H2 to grams using its molar mass.
How many moles of hydrogen gas contained in 9.03x1023?
Given/Known:1mole of H2 = 2.01588g H21mole of H2 = 6.022 x 1023 molecules H21) Convert molecules of H2 to moles of H2 by doing the following calculation.9.4 x 1025 molecules H2 x (1mol H2/6.022 x 1023 molecules H2) = 156mol H22) Convert the moles of H2 to mass in grams of H2.156mol H2 x (2.01588g H2/1mol H2) = 314g H2
How many moles of NH3 are produced when 1.4 moles H2 reacts?
Balanced equation. N2 + 3H2 --> 2NH3 1.4 moles H2 (2 moles NH3/3 moles H2) = 0.93 moles NH3 produced =======================
How many moles of H2 are needed to produce 8.25 mole of H2O?
2H2 + O2 --> 2H2OFor every 2 moles of H2, 2 moles of H2O will be produced (i.e., a 1:1 ratio). So to produce 8.25 moles of H2O you will also need 8.25 moles of H2
How many moles of molecules are there in 40.5 g of H2?
To determine the number of moles in 40.5 g of H2, first find the molar mass of H2, which is 2 grams per mole. Next, divide the given mass by the molar mass to find the number of moles. In this case, 40.5 g / 2 g/mol = 20.25 moles of H2.
What is the mass of 4 moles of hydrogen molecules (H2)?
8.086g
How many moles of H2 are there in 49.8 grams of H2?
1 mole of sulfuric acid=98g(?)chemical formula of sulfuric acid=H2SO4Atomic mass of Hydrogen(H)=1Atomic mass of Sulpher(S)=32Atomic mass of Oxygen(O)=16(1)2+32+(16)4=2+32+64=98uTo calculate number of molesNo. of moles=given mass/atomic massno. of moles=49/98no. of moles is 0.5g
What is the mass of 4 moles of CO2?
Hydrogen gas is H2. 1 moles H2 has a molar mass of 2.0158. Thus, 4 moles H2 gas has a mass of2.0158 g/mole x 4 moles = 8.063 g
How many grams of H2 are needed to produce 14.84 g of NH3?
To find the grams of H2 needed, we first calculate the moles of NH3 using its molar mass. Then, we use the balanced chemical equation to determine the mole ratio of H2 to NH3. Finally, we convert moles of H2 to grams using its molar mass.
How many moles of hydrogen gas contained in 9.03x1023?
Given/Known:1mole of H2 = 2.01588g H21mole of H2 = 6.022 x 1023 molecules H21) Convert molecules of H2 to moles of H2 by doing the following calculation.9.4 x 1025 molecules H2 x (1mol H2/6.022 x 1023 molecules H2) = 156mol H22) Convert the moles of H2 to mass in grams of H2.156mol H2 x (2.01588g H2/1mol H2) = 314g H2
How many moles of NH3 are produced when 1.4 moles H2 reacts?
Balanced equation. N2 + 3H2 --> 2NH3 1.4 moles H2 (2 moles NH3/3 moles H2) = 0.93 moles NH3 produced =======================
How many moles of H2 are needed to produce 8.25 mole of H2O?
2H2 + O2 --> 2H2OFor every 2 moles of H2, 2 moles of H2O will be produced (i.e., a 1:1 ratio). So to produce 8.25 moles of H2O you will also need 8.25 moles of H2
If you have 3.64 g of H2 how many grams of NH3 can be produced?
To determine how many grams of NH3 can be produced from 3.64 g of H2, we first need to use the balanced chemical equation for the synthesis of ammonia: N2 + 3H2 → 2NH3. The molar mass of H2 is approximately 2.02 g/mol, so 3.64 g of H2 is about 1.80 moles. According to the reaction, 3 moles of H2 produce 2 moles of NH3, so 1.80 moles of H2 would produce approximately 1.20 moles of NH3. The molar mass of NH3 is about 17.03 g/mol, resulting in about 20.4 grams of NH3 produced.
calculate the number of moles in H2 molecules in 4g H2?
2 moles.
What is the mass of water when 4gm hydrogen and 64gm oxygen combined together nd how?
Balanced equation first.2H2 + O2 --> 2H2OGet moles products.4 grams H2 (1 mole H2/2.016 grams) = 1.984 moles H264 grams O2 (1 mole O2/32 grams) = 2.000 moles O2I suspect hydrogen gas of limiting and driving the reaction.1.984 moles H2 (1 mole O2/2 moles H2) = 0.992 moles O2 ( you have more than this in equation )2.000 moles O2 (2 mole H2/1 mole O2) = 4.000 moles H2 ( you do not have this much and H2 will drive this reaction )1.984 moles H2 (2 moles H2O/2 moles H2)(18.016 grams/1 mole H2O)= 36 grams water produced====================
How many molecules (not moles) of NH3 are produced from 5.69104 g of H2?
The reaction would be H2 + 3N2 ==>2NH3moles H2 used = 5.69104 g x 1 mole/2.00 = 2.84552 moles H2moles NH3 produced (assuming N2 is NOT limiting) = 2 moles NH3/mole H2 x 2.84552 moles H2 = 5.69104 moles NH3 producedMolecules of NH3 produced = 5.69104 moles x 6.02x10^23 molecules/mole = 3.4x10^24 molecules
