I assume you mean the molecular mass. Its molecular mass is 367.01g/mol
The molar mass of PbBr2 is 367.008 g/mol
PbI does not exist. There are, however PbI2 and PbI4. Neither are good electrolytes.
The chemical equation is:Pb(NO3)2 + BaBr2 = PbBr2 + Ba(NO3)2
The formula of lead(II) bromide is PbBr2. Lead has a 2+ charge, while bromine has a 1- charge, so it takes two bromine atoms to balance out the charge on one lead atom.
The binary compound formula for plumbic bromide is PbBr2.
The molar mass of PbBr2 is 367.008 g/mol
1.2x10-2
PbBr2 is only slightly soluble in water, but more so than PbCl2, so if you had to write the equation it would be2LiCl(aq) + PbBr2(aq) ==> 2LiBr(aq) + PbCl2(s)
The chemical formula for Lead (II) Bromide is - PbBr2
The solubility of PbBr2 at 25°C can be calculated using the Ksp value. Since PbBr2 dissociates into Pb2+ and 2 Br- ions, the solubility (S) can be found using the expression Ksp = [Pb2+][Br-]^2. By substituting the given Ksp value into the equation, you can solve for the solubility of PbBr2 at 25°C.
The formula for Led II Bromide is PbBr2. It is a non organic compound and is a result of leaded gasoline burning.
PbBr2
The molar solubility of PbBr2 in water is approximately 1.6 x 10^-3 mol/L at 25°C. This means that at this temperature, 1.6 x 10^-3 moles of PbBr2 will dissolve in one liter of water.
PbI does not exist. There are, however PbI2 and PbI4. Neither are good electrolytes.
Lead(II) Bromide = PbBr2
Lead(II) Bromide = PbBr2
The molecular formula for Plumbic Bromide is PbBr2