no
The solubility of PbBr2 at 25°C can be calculated using the Ksp value. Since PbBr2 dissociates into Pb2+ and 2 Br- ions, the solubility (S) can be found using the expression Ksp = [Pb2+][Br-]^2. By substituting the given Ksp value into the equation, you can solve for the solubility of PbBr2 at 25°C.
To calculate the molar solubility of lead thiocyanate in 0.500 L of water, you need to know the Ksp value for lead thiocyanate. Can you provide that information?
Find the constant, which i think is 3.7*10^-4 and multiply it by 1.0. and you should get your answer
PbBr2 is only slightly soluble in water, but more so than PbCl2, so if you had to write the equation it would be2LiCl(aq) + PbBr2(aq) ==> 2LiBr(aq) + PbCl2(s)
The molar solubility of silver oxalate can be calculated using the given Ksp value. First, calculate the solubility product (Ksp) by taking the square root of the given value, which is √(5.4x10^12) ≈ 2.3x10^6. This means the molar solubility of silver oxalate is approximately 2.3x10^-6 mol/L.
The molar mass of PbBr2 is 367.008 g/mol
The solubility of PbBr2 at 25°C can be calculated using the Ksp value. Since PbBr2 dissociates into Pb2+ and 2 Br- ions, the solubility (S) can be found using the expression Ksp = [Pb2+][Br-]^2. By substituting the given Ksp value into the equation, you can solve for the solubility of PbBr2 at 25°C.
I assume you mean the molecular mass. Its molecular mass is 367.01g/mol
1.2x10-2
To calculate the molar solubility of lead thiocyanate in 0.500 L of water, you need to know the Ksp value for lead thiocyanate. Can you provide that information?
Find the constant, which i think is 3.7*10^-4 and multiply it by 1.0. and you should get your answer
Not really.Strontium carbonate can only dissolve in water at the rate of about 0.1g/L. However, it dissolves more readily in dilute acids (causing a reaction--strontium carbonate is a base) and in fully-carbonated water.
PbBr2 is only slightly soluble in water, but more so than PbCl2, so if you had to write the equation it would be2LiCl(aq) + PbBr2(aq) ==> 2LiBr(aq) + PbCl2(s)
The molar solubility of silver oxalate can be calculated using the given Ksp value. First, calculate the solubility product (Ksp) by taking the square root of the given value, which is √(5.4x10^12) ≈ 2.3x10^6. This means the molar solubility of silver oxalate is approximately 2.3x10^-6 mol/L.
The formula for Led II Bromide is PbBr2. It is a non organic compound and is a result of leaded gasoline burning.
In a saturated solution: [Pb2+] = 1.2x10-2 mol/L [Br-] = 2.4x10-2 mol/L because [Pb2+]*[Br-]2 = Ks = 6.3*10-6 and [Br-] = 2*[Pb2+]
The salt with the greatest solubility in water at 25 degrees Celsius is generally the one with the highest molar solubility. Factors affecting solubility include the nature of the cation and anion, as well as any common ions present. It is recommended to consult solubility tables or data for specific values.