PbBr2 is only slightly soluble in water, but more so than PbCl2, so if you had to write the equation it would be
2LiCl(aq) + PbBr2(aq) ==> 2LiBr(aq) + PbCl2(s)
The solubility of PbBr2 at 25°C can be calculated using the Ksp value. Since PbBr2 dissociates into Pb2+ and 2 Br- ions, the solubility (S) can be found using the expression Ksp = [Pb2+][Br-]^2. By substituting the given Ksp value into the equation, you can solve for the solubility of PbBr2 at 25°C.
The molar solubility of PbBr2 in water is approximately 1.6 x 10^-3 mol/L at 25°C. This means that at this temperature, 1.6 x 10^-3 moles of PbBr2 will dissolve in one liter of water.
To find the concentration of LiCl, first convert the mass of LiCl to moles. The molar mass of LiCl is approximately 42.39 g/mol, so 2.5 grams of LiCl is about 0.059 mol (2.5 g ÷ 42.39 g/mol). The concentration in mol/L (M) is then calculated by dividing the number of moles by the volume in liters: 0.059 mol ÷ 0.045 L = 1.31 M. Thus, the concentration of LiCl in the solution is approximately 1.31 M.
The molecular formula for Plumbic Bromide is PbBr2
You know because of solubility rules that LiCl disassociates 100% in water. So, knowing that molarity is equal to moles/liters Molarity LiCl = 1.97mol / 33.2 L Molarity = 0.059 M LiCl
LiOH + HCl -> LiCl + H2O This is an acid base neutralization reaction producing a salt, lithium chloride (LiCl ) and water.
The chemical equation for the reaction between hydrochloric acid (HCl) and lithium hydroxide (LiOH) is: HCl + LiOH -> LiCl + H2O This reaction produces lithium chloride (LiCl) as a salt and water (H2O) as a product.
When lithium chloride (LiCl) reacts with sulfuric acid (H2SO4), it forms lithium sulfate (Li2SO4) and hydrochloric acid (HCl). The balanced chemical equation is: 2LiCl + H2SO4 -> Li2SO4 + 2HCl.
I assume you mean the molecular mass. Its molecular mass is 367.01g/mol
1.2x10-2
lead + bromine ---> lead bromide Pb + Br2 ---> PbBr2 As a chemical compound containing lead, it is categorised as probably carcinogenic to humans. It is a white powder at room temperature.
LiCl is the compound lithium chloride.
The molar mass of PbBr2 is 367.008 g/mol
The chemical formula for Lead (II) Bromide is - PbBr2
The solubility of PbBr2 at 25°C can be calculated using the Ksp value. Since PbBr2 dissociates into Pb2+ and 2 Br- ions, the solubility (S) can be found using the expression Ksp = [Pb2+][Br-]^2. By substituting the given Ksp value into the equation, you can solve for the solubility of PbBr2 at 25°C.
The formula for Led II Bromide is PbBr2. It is a non organic compound and is a result of leaded gasoline burning.
The cation in LiCl is Li+ (lithium ion).