PbBr2 is only slightly soluble in water, but more so than PbCl2, so if you had to write the equation it would be
2LiCl(aq) + PbBr2(aq) ==> 2LiBr(aq) + PbCl2(s)
The solubility of PbBr2 at 25°C can be calculated using the Ksp value. Since PbBr2 dissociates into Pb2+ and 2 Br- ions, the solubility (S) can be found using the expression Ksp = [Pb2+][Br-]^2. By substituting the given Ksp value into the equation, you can solve for the solubility of PbBr2 at 25°C.
The molar solubility of PbBr2 in water is approximately 1.6 x 10^-3 mol/L at 25°C. This means that at this temperature, 1.6 x 10^-3 moles of PbBr2 will dissolve in one liter of water.
The molecular formula for Plumbic Bromide is PbBr2
You know because of solubility rules that LiCl disassociates 100% in water. So, knowing that molarity is equal to moles/liters Molarity LiCl = 1.97mol / 33.2 L Molarity = 0.059 M LiCl
LiCl
LiOH + HCl -> LiCl + H2O This is an acid base neutralization reaction producing a salt, lithium chloride (LiCl ) and water.
The chemical equation for the reaction between hydrochloric acid (HCl) and lithium hydroxide (LiOH) is: HCl + LiOH -> LiCl + H2O This reaction produces lithium chloride (LiCl) as a salt and water (H2O) as a product.
When lithium chloride (LiCl) reacts with sulfuric acid (H2SO4), it forms lithium sulfate (Li2SO4) and hydrochloric acid (HCl). The balanced chemical equation is: 2LiCl + H2SO4 -> Li2SO4 + 2HCl.
I assume you mean the molecular mass. Its molecular mass is 367.01g/mol
1.2x10-2
LiCl is the compound lithium chloride.
lead + bromine ---> lead bromide Pb + Br2 ---> PbBr2 As a chemical compound containing lead, it is categorised as probably carcinogenic to humans. It is a white powder at room temperature.
The molar mass of PbBr2 is 367.008 g/mol
The chemical formula for Lead (II) Bromide is - PbBr2
The solubility of PbBr2 at 25°C can be calculated using the Ksp value. Since PbBr2 dissociates into Pb2+ and 2 Br- ions, the solubility (S) can be found using the expression Ksp = [Pb2+][Br-]^2. By substituting the given Ksp value into the equation, you can solve for the solubility of PbBr2 at 25°C.
The cation in LiCl is Li+ (lithium ion).
The formula for Led II Bromide is PbBr2. It is a non organic compound and is a result of leaded gasoline burning.