the answer is 4.0 g
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Divide 96 by molecular mass.So the answer is 6mol
The atomic mass of the organic compound CH3OH is 12.0 + 3.0 + 16.0 + 1.0 = 32.0Amount of CH3OH = mass of pure sample/molar mass = 5.00/32.0 = 0.156molThere are 0.156 moles of CH3OH in a 5.00 gram pure sample.
Divide 2.52 by molecular mass 16.Then multiply by avagadro constant
The answer depends on sample of WHAT!
The volume and the mass of sample both depend on the size of the sample.A small sample has small volume and small mass, a big sample has big volumeand big mass. But the ratio of mass to volume is constant for a pure sample ofa substance, no matter what size the sample is. That ratio is called the densityof the substance.
300K
5600
Divide 96 by molecular mass.So the answer is 6mol
The atomic mass of the organic compound CH3OH is 12.0 + 3.0 + 16.0 + 1.0 = 32.0Amount of CH3OH = mass of pure sample/molar mass = 5.00/32.0 = 0.156molThere are 0.156 moles of CH3OH in a 5.00 gram pure sample.
7.48
Divide 2.52 by molecular mass 16.Then multiply by avagadro constant
The volume of a sample of water is 20 cm3. The mass of this sample is closest to
The answer depends on sample of WHAT!
This mass is 6,416 g.
The volume and the mass of sample both depend on the size of the sample.A small sample has small volume and small mass, a big sample has big volumeand big mass. But the ratio of mass to volume is constant for a pure sample ofa substance, no matter what size the sample is. That ratio is called the densityof the substance.
Mass is an extensive property, which depends only on the amount of matter in the sample, not on the composition of the sample.
Take the balanced equation CH4+2O2---->CO2+2H2O.So according to it 40g of O2