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What is the mass of 5.0 moles of CH4?
The atomic mass of the organic compound CH3OH is 12.0 + 3.0 + 16.0 + 1.0 = 32.0Amount of CH3OH = mass of pure sample/molar mass = 5.00/32.0 = 0.156molThere are 0.156 moles of CH3OH in a 5.00 gram pure sample.
How many moles of CH4 are present in 6.07 g of (CH4)?
Divide 96 by molecular mass.So the answer is 6mol
How many moles of CH4 are in 200 grams of CH4?
200 g CH4 x 1 mole CH4/16 g = 12.5 moles CH4
What mass of oxygen is required to completely react with 20 grams of CH4?
To calculate the mass of oxygen required to react with 20 grams of CH4, we first need to write and balance the chemical equation for the reaction. The balanced equation for the combustion of CH4 is: CH4 + 2O2 → CO2 + 2H2O This equation tells us that 1 mole of CH4 reacts with 2 moles of O2. The molar mass of CH4 is 16 g/mol. Therefore, 20 grams of CH4 is equal to 20/16 = 1.25 moles CH4. So, 1.25 moles of CH4 would require 2.50 moles of O2. The molar mass of O2 is 32 g/mol. Therefore, the mass of O2 required would be 2.50 moles * 32 g/mol = 80 grams.
How many molecules of CH4 are in 2.52 mol of CH4?
Divide 2.52 by molecular mass 16.Then multiply by avagadro constant
Calculate the temperature of a 969 mL sample of CH4 gas at 104 kPa with a mass of 0.647 g?
300K
What is the mass of 5.0 moles of CH4?
The atomic mass of the organic compound CH3OH is 12.0 + 3.0 + 16.0 + 1.0 = 32.0Amount of CH3OH = mass of pure sample/molar mass = 5.00/32.0 = 0.156molThere are 0.156 moles of CH3OH in a 5.00 gram pure sample.
What is 56L equal to?
5600
How many moles of CH4 are present in 6.07 g of (CH4)?
Divide 96 by molecular mass.So the answer is 6mol
How many moles of CH4 are in 200 grams of CH4?
200 g CH4 x 1 mole CH4/16 g = 12.5 moles CH4
What mass of oxygen is required to completely react with 20 grams of CH4?
To calculate the mass of oxygen required to react with 20 grams of CH4, we first need to write and balance the chemical equation for the reaction. The balanced equation for the combustion of CH4 is: CH4 + 2O2 → CO2 + 2H2O This equation tells us that 1 mole of CH4 reacts with 2 moles of O2. The molar mass of CH4 is 16 g/mol. Therefore, 20 grams of CH4 is equal to 20/16 = 1.25 moles CH4. So, 1.25 moles of CH4 would require 2.50 moles of O2. The molar mass of O2 is 32 g/mol. Therefore, the mass of O2 required would be 2.50 moles * 32 g/mol = 80 grams.
What is the mass (by difference) of a sample if the initial mass of the sample in the bottle was 28.81-g and the final mass of the bottle and sample was 21.33-g?
7.48
How many molecules of CH4 are in 2.52 mol of CH4?
Divide 2.52 by molecular mass 16.Then multiply by avagadro constant
What mass of natural gas CH4 must you burn to emit 267 kJ of heat?
First, determine the heat of combustion for CH4, which is -802 kJ/mol. Then, calculate the number of moles of CH4 needed to emit 267 kJ of heat. Finally, convert the moles of CH4 to grams using the molar mass of CH4 (16 g/mol).
How to find the percent by mass of a compound in a given sample?
To find the percent by mass of a compound in a given sample, you need to divide the mass of the compound by the total mass of the sample and then multiply by 100. This will give you the percentage of the compound in the sample.
What mass of natural gas CH4 must you burn to emit 270kJ of heat?
To calculate the mass of natural gas burned, we need to use the heat of combustion of methane, which is -890 kJ/mol. This means that 1 mol of CH4 produces 890 kJ of heat. Therefore, to emit 270 kJ of heat, you would need to burn 270/890 = 0.303 mol of CH4. The molar mass of CH4 is 16.05 g/mol, so the mass of CH4 needed would be 0.303 mol * 16.05 g/mol = 4.86 g.
How many mole of CH4 are in 96.0 grams of CH4?
Divide 96 by molecular mass.So the answer is 6mol
