The Atomic Mass of the organic compound CH3OH is 12.0 + 3.0 + 16.0 + 1.0 = 32.0Amount of CH3OH = mass of pure sample/molar mass = 5.00/32.0 = 0.156molThere are 0.156 moles of CH3OH in a 5.00 gram pure sample.
5.90 mol CH x 13.0189 gCH / 1 mol CH = 76.81 g CH
80g
Divide 96 by molecular mass.So the answer is 6mol
200 g CH4 x 1 mole CH4/16 g = 12.5 moles CH4
Molar mass:O2 32 g/molCH4 16 g/molReaction:CH4 + 2 O2 --> CO2 + 2H2OCalculus1 mol CH4 with 2 moles O2Given: 24 g CH4 equals 24/16 = 1.5 mol CH4this will need 2 * 1.5 moles O2 = 3.0 mol O23.0 mol O2 equals 3.0 * 32 = 96 g O2
CH4 + 2 H2O = 3 H2 + CO2 8 moles CH4 produce 8 x 3 moles H2, which is 24.
Methane is CH4. Combustion is CH4 + 2O2 ==> CO2 + 2H2O1 mole CH4 produces 2 moles H2Omoles CH4 used = 1.1x10^-3 g x 1 mole/16 g = 6.875x10^-5 molesmoles H2O produced = 6.875x10^-5 moles CH4 x 2 moles H2O/mole CH4 = 1.375x10^-4 molesmass H2O produced = 1.375x10^-4 moles x 18 g/mole = 2.475x10^-3 g = 2.48 mg (3 sig.figs)
Divide 96 by molecular mass.So the answer is 6mol
There are 0.75 moles in it.You have to devide 12 by molecular mass
This mass is 6,416 g.
200 g CH4 x 1 mole CH4/16 g = 12.5 moles CH4
First, determine molar mass of CH4: C:12g/mol + 4x H:1g/mol= 16g/mol Then divide by the number of grams. 64g/(16g/mol)= 4 moles of CH4
That's a tricky question, because one molecule of CH4 is simply that, one atom of carbon and 4 atoms of Hydrogen. Moles are a UNIT used to transform atoms (which we cannot measure individually in the lab) into practical units such as grams (which we can measure). The moles of CH4 depend on the mass, in SI units of grams, that you have of this substance. The molecular weight of CH4 is 16 g/mol (12 for Carbon + 1 for each Hydrogen). If you WANTED 2 moles of CH4, you need to multiply this molecular weight by 2 moles to get 32 grams (the moles cancel out upon multiplication). So, 32 grams of CH4 is 2 moles of CH4.
I think you are asking for the mass of 0.35 moles of methane (CH4). First, we find the molecular mass of methane by addin the masses of all of the atoms. A carbon is 12, and each H is 1, so the molecular mass of CH4 is 16g/mole. Now we multiply 0.35 moles by 16 g/mole. The moles cancel out, and we have 5.6 g.
Molar mass:O2 32 g/molCH4 16 g/molReaction:CH4 + 2 O2 --> CO2 + 2H2OCalculus1 mol CH4 with 2 moles O2Given: 24 g CH4 equals 24/16 = 1.5 mol CH4this will need 2 * 1.5 moles O2 = 3.0 mol O23.0 mol O2 equals 3.0 * 32 = 96 g O2
The balanced equation for combustion of CH4 is CH4 + 2O2 ==> CO2 + 2H2OThus, one mole CH4 produces 1 mole CO21 g CH4 x 1 mole CH4/16 g = 0.0625 moles CH40.0625 moles CH4 ==> 0.0625 moles CO20.0625 moles CO2 x 44 g CO2/mole = 2.75 g CO2Thus, the answer would be that 1 grams of CH4 will produce 2.75 grams of CO2 after complete combustion.
Mass of 4 mole CO2 , this is 4 * (12 + 2*16) = 176 grams
In 3 moles of CH4, there are 18.06 x 10^23 times Hydrogen atoms.
CH4 + 2 H2O = 3 H2 + CO2 8 moles CH4 produce 8 x 3 moles H2, which is 24.