The molar mass of magnesium bromide is approximately 203 g/mol.
The molar mass of calcium bromide is........99,88.
Potassium bromide is KBr, so by adding together their molar masses, we get 39+80=119gmol-1
The molar mass of KBr is 119.0023 g/mol
To find the number of moles in 1.2 kg of calcium bromide, you first need to determine the molar mass of calcium bromide (CaBr2), which is approximately 199.89 g/mol. Then convert the mass of 1.2 kg to grams (1200 g). Finally, divide the mass in grams by the molar mass to find the number of moles. In this case, 1200g / 199.89g/mol ≈ 6 moles of calcium bromide.
That is a lot of calcium bromide we are dealing with. The formula mass of calcium bromide, CaBr2 is 40.1 + 2(79.9) = 199.9.Amount of CaBr2 = (7.4 x 1000)/199.9 = 32.0mol There are 32 moles of calcium bromide in a 7.4kg pure sample.
The molar mass of calcium bromide is........99,88.
Sodium iodide has the highest molar mass among the compounds listed, with a molar mass of 149.89 g/mol. Sodium bromide has a molar mass of 102.89 g/mol, sodium chloride has a molar mass of 58.44 g/mol, lithium bromide has a molar mass of 86.85 g/mol, and lithium fluoride has a molar mass of 25.94 g/mol.
Potassium bromide is KBr, so by adding together their molar masses, we get 39+80=119gmol-1
The molar mass of calcium bromide (CaBr2) is 199.89 g/mol. Calcium has a molar mass of 40.08 g/mol. The mass percent of calcium in calcium bromide is calculated as (40.08 g/mol / 199.89 g/mol) x 100%, which is approximately 20.04%.
To find the number of moles in 245g of potassium bromide, first calculate the molar mass of KBr by adding the atomic masses of potassium (39.10 g/mol) and bromine (79.90 g/mol). The molar mass of KBr is 119.00 g/mol. Then, divide the given mass by the molar mass: 245g / 119.00 g/mol = 2.06 moles of potassium bromide.
The atomic mass of magnessium is 24.3050
The molar mass of KBr is 119.0023 g/mol
To find the number of moles in 1.2 kg of calcium bromide, you first need to determine the molar mass of calcium bromide (CaBr2), which is approximately 199.89 g/mol. Then convert the mass of 1.2 kg to grams (1200 g). Finally, divide the mass in grams by the molar mass to find the number of moles. In this case, 1200g / 199.89g/mol ≈ 6 moles of calcium bromide.
That is a lot of calcium bromide we are dealing with. The formula mass of calcium bromide, CaBr2 is 40.1 + 2(79.9) = 199.9.Amount of CaBr2 = (7.4 x 1000)/199.9 = 32.0mol There are 32 moles of calcium bromide in a 7.4kg pure sample.
To calculate the mass of calcium bromide needed, you would first find the number of moles needed using the equation moles = Molarity * Volume (in liters). Then, you would use the molar mass of calcium bromide to convert moles to grams. The molar mass of calcium bromide is 199.89 g/mol.
The molar volume of a gas at STP is 22.4 liters/mol. The molar mass of hydrogen bromide is 80.9 g/mol. Therefore, the density of hydrogen bromide at STP is 80.9 g/mol / 22.4 L/mol = 3.61 g/L.
you take the mass of Al plus three Br. (27.0) + 3(80.0) the answer is 267.