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Molar mass of HNO3 =63g

Given mass= 12.6g

No. of moles=12.6/63=0.2 moles

Molarity= No. of moles/Volume of solution(in litre)

= 0.2/0.5=0.4 M

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14y ago
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10y ago

First we multiply by 4 to make it per litre. 12*4 is 48g. Next we divide by 40 (m wt of NaOH). 48/40 is 1.2 molar.

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Q: What is the molarity of a solution of HNO3 which contains 12.6grams of solute in 500 mL of soulution?
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