Molar mass of HNO3 =63g
Given mass= 12.6g
No. of moles=12.6/63=0.2 moles
Molarity= No. of moles/Volume of solution(in litre)
= 0.2/0.5=0.4 M
First we multiply by 4 to make it per litre. 12*4 is 48g. Next we divide by 40 (m wt of NaOH). 48/40 is 1.2 molar.
This molarity is approx. o,89.
The molarity is 0,031.
Molarity = moles of solute/Liters of solution Molarity = 0.202 moles KCl/7.98 Liters = 0.253 M KCl solution ================
Molarity=no. of moles of solute/vol of solution in(L) molarity=0.4/9.79=0.04086 mol L-1=0.04086 M.
31 grams HCl (1mol/36.458g ) = 0.850 moles 500cm^3 = 0.50 Liters Molarity = moles of solute/liters of solution Molarity = 0.850mol/0.50L = 1.7 Molarity
This molarity is approx. o,89.
The molarity is 0,041
The molarity is 0,025.
If 1,1 is grams the molarity is 0,317.
This molarity is 1,59.
The molarity is 0,031.
Molarity = moles of solute/Liters of solution Molarity = 0.202 moles KCl/7.98 Liters = 0.253 M KCl solution ================
A neutral solution.
The molar mass of KMnO4 is 158,3415 g.The molarity of this solution is 0,1 M.
The molarity is 0.718 moles/litre.
This molarity is 0,207 mol.
Molarity=no. of moles of solute/vol of solution in(L) molarity=0.4/9.79=0.04086 mol L-1=0.04086 M.