0
V1= [V2 * M2] / M1 = [5.00 (L) * 3.00 (mol/L)] / 12.6 (mol/L) = 15.0/12.6 = 1.19 L
So carefully add a volume of 1.19 L of 12.6M HCl, as accurately as possible to about 3.5 L Water in a 5.00 L calibrated glass cylinder and fill this up to the 5L mark after mixing.
Wiki User
∙ 12y ago
Wiki User
∙ 12y agoThere are 8.33 * 10^(-3) moles of H+ in your solution
pH = -log [H+]
[H+] = 10^(-pH)
[H+] = 0.001 mol/L
n = C / V
n = 0.001 / 0.120
n = 0.008333... mol
Wiki User
∙ 15y ago12 M = 12 moles HCl per 1 liter of solution...so 12 moles/ 1 liter = 3 moles/ X liters. X = 0.25 liters of 250mL
Wiki User
∙ 10y ago>(0.600 M)(300mL) = 180
>180/12.0= 15.0mL
Hope this helps. =))
Wiki User
∙ 10y ago3/12 = 0.25 molar or 0.25 M
Wiki User
∙ 7y agoThe answer is 36 moles HCl.
Wiki User
∙ 13y ago0.25 M
Wiki User
∙ 12y ago0.25M
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