The mole fraction must be calculated in moles solvent over moles solution. So, 3.4 grams sulfuric acid equals .0347 moles sulfuric acid. 3500 mL water equals 3500 g water equals 194 mols. .0347 mols/(.0347+194) = 1/5591.77 mols/mol
try adding ten grams to every liter
512 GRAMS Divide the quantity by the SG: EG1000 litres divide by 1.28 = 781.25 litres per tonne. dumb*** has to use percent sulfuric acid .4*.391=.1564 *1000=156ml of sulfuric acid 156*1.28=200.2 grams H2SO4 in .4L and is 5.1M
It would be 98 grams.
It would have a mass of 98 grams.
40g/ lit of sulfuric acid is is 2.22%
This solution contain 2,89 g sulfuric acid.
try adding ten grams to every liter
512 GRAMS Divide the quantity by the SG: EG1000 litres divide by 1.28 = 781.25 litres per tonne. dumb*** has to use percent sulfuric acid .4*.391=.1564 *1000=156ml of sulfuric acid 156*1.28=200.2 grams H2SO4 in .4L and is 5.1M
It would be 98 grams.
It would have a mass of 98 grams.
Mass percent = grams of solute/total grams of solution Mole fraction = mols component/total mols mix. Molarity = mols solute/L solution Molality = mols solute/kg solvent Hope this helps :)
20% salt solution is the equivalent of adding 200gr salt in a 800 ml (1000ml -200ml) of water. you now have one liter of a 20% solution.
40g/ lit of sulfuric acid is is 2.22%
This is the number of grams of solute in 100 grams of solution. As an example, a 5%w/w solution in water is prepared by dissolving 5 grams of solute in water and then adding further water with mixing until the final weight is 100 gram.
It is 98.086 grams per mole.
M refers to molar. Molarity is the number of moles of a solute dissolved in one liter of solvent. 3M means there are 3 moles of sulfuric acid in one liter, and 9M means 9 moles of sulfuric acid are dissolved in one liter.
The mass of sulfuric acid is 490,395 grams.