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The mole fraction must be calculated in moles solvent over moles solution. So, 3.4 grams sulfuric acid equals .0347 moles sulfuric acid. 3500 mL water equals 3500 g water equals 194 mols. .0347 mols/(.0347+194) = 1/5591.77 mols/mol

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Q: What is the mole fraction of sulfuric acid in a solution made by adding 3.4 grams of sulfuric acid to 3500 mL of water?
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