2H = 2.016 grams
1S = 32.07 grams
4O = 64 grams
-------------------------------add
= 98.086 grams/mole
===============
1 mole H2SO4 x 4 moles O/mole H2SO4 x 6.02x10^23 atoms of O/mole O = 2.4x10^34 oxygen atoms
The molar mass of sulfuric acid (H2SO4) is 98.08 grams/mole. Therefore, there are 98.08 grams in 1 mole of sulfuric acid.
Grams NaOH?? Balanced equation. 2NaOH + H2SO4 --> Na2SO4 + 2H2O 4.9 grams H2SO4 (1 mole H2SO4/98.086 grams)(2 mole NaOH/1 mole H2SO4)(39.998 grams/1 mole NaOH) = 4.0 grams NaOH needed =================
2 moles of NaOH will react with 1 mole of H2SO4 based on the balanced chemical equation: 2NaOH + H2SO4 -> Na2SO4 + 2H2O.
There are 5 moles of sulfur in 5 moles of H2SO4, as there is 1 mole of sulfur in each mole of H2SO4.
1 mole H2SO4 x 4 moles O/mole H2SO4 x 6.02x10^23 atoms of O/mole O = 2.4x10^34 oxygen atoms
The molar mass of sulfuric acid (H2SO4) is 98.08 grams/mole. Therefore, there are 98.08 grams in 1 mole of sulfuric acid.
Grams NaOH?? Balanced equation. 2NaOH + H2SO4 --> Na2SO4 + 2H2O 4.9 grams H2SO4 (1 mole H2SO4/98.086 grams)(2 mole NaOH/1 mole H2SO4)(39.998 grams/1 mole NaOH) = 4.0 grams NaOH needed =================
2 moles of NaOH will react with 1 mole of H2SO4 based on the balanced chemical equation: 2NaOH + H2SO4 -> Na2SO4 + 2H2O.
There are 5 moles of sulfur in 5 moles of H2SO4, as there is 1 mole of sulfur in each mole of H2SO4.
Quite a few! 335 moles H2SO4 (4 moles O/1 mole H2SO4)(6.022 X 1023/1 mole O) = 8.07 X 1026 atoms of oxygen =======================
A mole of sulfuric acid (H2SO4) contains one mole of sulfur (S), two moles of hydrogen (H), and four moles of oxygen (O).
The balanced chemical equation between potassium hydroxide (KOH) and sulfuric acid (H2SO4) is: 2 KOH + H2SO4 -> K2SO4 + 2 H2O This equation shows that 2 moles of KOH react with 1 mole of H2SO4 to produce 1 mole of K2SO4 and 2 moles of water.
The balanced chemical equation for the reaction between magnesium hydroxide (Mg(OH)2) and sulfuric acid (H2SO4) is: Mg(OH)2 + H2SO4 -> MgSO4 + 2H2O. From the equation, 1 mole of Mg(OH)2 will produce 2 moles of water (H2O) when it reacts with 1 mole of H2SO4.
1 gm mole of Sulphuric Acid (H2SO4) weights 98 gm.
2 moles H2SO4 (98.086 grams/1 mole H2SO4)= 196.172 grams of sulfuric acid====================
196 grams H2SO4 (1 mole H2SO4/98.096 grams)(6.022 X 10^23/1 mole H2SO4) = 1.20 X 10^24 molecules of sulfuric acid