The net ionic equation for the reaction between lead(II) nitrate (Pb(NO3)2) and sodium carbonate (Na2CO3) is:
Pb^2+ + CO3^2- -> PbCO3 (s)
This equation shows that lead(II) ions from lead nitrate react with carbonate ions from sodium carbonate to form solid lead carbonate.
BaCl2 + Na2CO3 -> BaCO3 + 2NaCl
Balanced equation: Cu(CH3COO)2 + Na2CO3 -> CuCO3 + 2CH3COONa Net ionic equation: Cu^2+ + CO3^2- -> CuCO3
Molecular equation: CuSO4 + Na2CO3 → CuCO3 + Na2SO4 Net ionic equation: Cu2+ + CO3^2- → CuCO3
The net ionic equation for the reaction between HCl and Na2CO3 is 2H+ (aq) + CO3^2- (aq) -> H2O (l) + CO2 (g). This indicates the formation of water and carbon dioxide gas as products.
The net ionic equation for the reaction between Pb(NO3)2(aq) and Na2CO3(aq) is: Pb^2+ (aq) + CO3^2- (aq) → PbCO3 (s)
These two compounds doesn't react.
BaCl2 + Na2CO3 -> BaCO3 + 2NaCl
Balanced equation: Cu(CH3COO)2 + Na2CO3 -> CuCO3 + 2CH3COONa Net ionic equation: Cu^2+ + CO3^2- -> CuCO3
Molecular equation: CuSO4 + Na2CO3 → CuCO3 + Na2SO4 Net ionic equation: Cu2+ + CO3^2- → CuCO3
The net ionic equation for the reaction between HCl and Na2CO3 is 2H+ (aq) + CO3^2- (aq) -> H2O (l) + CO2 (g). This indicates the formation of water and carbon dioxide gas as products.
chromium disodium phosphate
The net ionic equation for the reaction between Pb(NO3)2(aq) and Na2CO3(aq) is: Pb^2+ (aq) + CO3^2- (aq) → PbCO3 (s)
The net ionic equation for the reaction between Na2CO3 and CaCl2 to form CaCO3 is: 2Na+ + CO3^2- + Ca^2+ + 2Cl- → CaCO3(s) + 2Na+ + 2Cl-. This equation represents the ions that are involved in the reaction, excluding spectator ions.
The net ionic equation for the reaction between sodium carbonate (Na2CO3) and hydrochloric acid (HCl) is: CO3^2- + 2H^+ -> H2O + CO2. This net ionic equation represents the reaction of carbonate ions with hydrogen ions to form water and carbon dioxide.
To determine the net ionic equation, write out the balanced molecular equation first. Then, write the complete ionic equation with all ions separated. Finally, cancel out spectator ions (ions that appear on both sides of the equation) to arrive at the net ionic equation, which shows only the reacting ions.
To write a net ionic equation from a complete ionic equation, you remove the spectator ions that appear on both sides of the equation. The remaining ions that participate in the reaction are then included in the net ionic equation. This simplifies the equation to show only the ions that undergo a chemical change.
Yes, it will neutralize the HCl and form carbonic acid, which is not stable and decomposes to form CO2. The overall reaction is: Na2CO3 + 2HCl ---> 2NaCl + H2O + CO2, and takes place in two stages: Stage I: sodium carbonate is converted to sodium hyrogen carbonate (NaHCO3) as shown in the reaction: Na2CO3 + HCl ---> NaHCO3 + NaCl Stage II: the gas, carbon dioxide is released NaHCO3 + HCl ---> NaCl + H20 + CO2 The net ionic equation is: CO32- + 2H+ ---> H2O + CO2