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The normality of 0.1 N acetate is 0.1 N. This means that there is 0.1 mole of acetic acid per liter of solution, assuming full dissociation of the acetate ions.

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How do you prepare 200ml of ethyl acetate of 0.1 Normality solution?

To prepare 200ml of 0.1 N ethyl acetate solution, you will need to calculate the amount of ethyl acetate needed. Since the molecular weight of ethyl acetate is around 88.11 g/mol, for 200ml of 0.1 N solution, you would need around 1.76g of ethyl acetate. Dissolve this amount of ethyl acetate in distilled water to make up the final volume to 200ml.


What is the normality if 25mL of 0.5 N NaOH is needed to neuralize 30 mL of the unknown acid solution?

The normality of the unknown acid solution is 0.625 N. This can be calculated by using the equation: Normality of acid x volume of acid = Normality of base x volume of base. Given that 25mL of 0.5 N NaOH neutralizes 30mL of the acid, you can set up the equation and solve for the normality of the acid.


What is the unit of normality?

The unit for normality is N, or mol/LN or mol/Lit is the unit


Who to calculated normality of iodine?

Normality of iodine ((I_2)) can be calculated using the formula: Normality = Molarity x n, where n is the oxidation state of iodine in the reaction. For example, if you are using a 0.1 M (I_2) solution in a redox reaction where iodine is being reduced to iodide ions ((I^-)), then the normality of iodine would be 0.1 N.


What does the N stand for in 0.02 N acid?

The N of 0.02 N acid stands for the "normality". The normality is defined as the gram equivalent weight of a substance in a liter of solution. so, a 0.02 acid would have 0.02 gram equivalents of acid per liter. In short N means "normality" and stands for "g/l"

Related Questions

How do you prepare 200ml of ethyl acetate of 0.1 Normality solution?

To prepare 200ml of 0.1 N ethyl acetate solution, you will need to calculate the amount of ethyl acetate needed. Since the molecular weight of ethyl acetate is around 88.11 g/mol, for 200ml of 0.1 N solution, you would need around 1.76g of ethyl acetate. Dissolve this amount of ethyl acetate in distilled water to make up the final volume to 200ml.


What is the normality if 25mL of 0.5 N NaOH is needed to neuralize 30 mL of the unknown acid solution?

The normality of the unknown acid solution is 0.625 N. This can be calculated by using the equation: Normality of acid x volume of acid = Normality of base x volume of base. Given that 25mL of 0.5 N NaOH neutralizes 30mL of the acid, you can set up the equation and solve for the normality of the acid.


What is the normality of an acid solution if 50 ml of the solution requires 48.6 ml of 0.1879 N alkali for neutralization?

The normality of the acid solution can be calculated using the formula: Normality of acid x Volume of acid = Normality of alkali x Volume of alkali. Plugging in the values, we get: Normality of acid x 50 ml = 0.1879 N x 48.6 ml. Solving for the normality of the acid gives approximately 0.186 N.


What is the unit of normality?

The unit for normality is N, or mol/LN or mol/Lit is the unit


Formula for normality to liquids?

Normality (N) of a liquid solution is calculated by dividing the number of equivalents of solute by the volume of solvent in liters. The formula for normality is N = (equivalents of solute) / (volume of solvent in liters).


Who to calculated normality of iodine?

Normality of iodine ((I_2)) can be calculated using the formula: Normality = Molarity x n, where n is the oxidation state of iodine in the reaction. For example, if you are using a 0.1 M (I_2) solution in a redox reaction where iodine is being reduced to iodide ions ((I^-)), then the normality of iodine would be 0.1 N.


What does the N stand for in 0.02 N acid?

The N of 0.02 N acid stands for the "normality". The normality is defined as the gram equivalent weight of a substance in a liter of solution. so, a 0.02 acid would have 0.02 gram equivalents of acid per liter. In short N means "normality" and stands for "g/l"


What is the normality of a 6.35 M H2SO4 is?

0.08 n


What is the difference between ethyl acetate and n propyl acetate?

Ethyl acetate has two carbons in its main chain, while n-propyl acetate has three carbons. This leads to differences in their physical properties such as boiling point and solubility. Ethyl acetate is commonly used as a solvent in paints and nail polish remover, while n-propyl acetate is used in flavorings and fragrances.


What is the normality of commercial grade HCl?

The normality of commercial grade hydrochloric acid (HCl) can vary depending on the concentration specified by the manufacturer. Hydrochloric acid is commonly available in different concentrations, such as 37% or concentrated hydrochloric acid. To determine the normality, it is essential to know the molarity (moles of solute per liter of solution) and the number of equivalents of the acid. Normality (N) is related to molarity (M) by the equation: � = � × � N=n×M where: � N is the normality, � n is the number of equivalents, � M is the molarity. For hydrochloric acid (HCl), which is a monoprotic acid (donates one proton), the number of equivalents ( � n) is equal to 1. Therefore, if you know the molarity of the commercial grade hydrochloric acid, you can determine its normality using the equation mentioned above. It's important to check the product label or contact the manufacturer for the specific concentration of the hydrochloric acid you are using.


What is lab normality of hcl?

The normality of a solution is a measure of the concentration of a solute in a solution. For HCl (hydrochloric acid), the normality would depend on the concentration of the HCl solution. For example, a 1 M (molar) solution of HCl would be 1 N (normal).


A 25.0 ml sample of hcl was titrated to the endpoint with 15.0 ml of 2.0 normality naoh what was the normality of th hcl what was its molarity?

The normality of HCl can be calculated using the equation: Normality (HCl) * Volume (HCl) = Normality (NaOH) * Volume (NaOH). Solving for the normality of HCl gives 6.0N. The molarity of the HCl solution can be calculated using the formula: Molarity = Normality / n-factor. Assuming the n-factor for HCl is 1, the molarity of the HCl solution would be 6.0 M.