-1 for oxygen in peroxides
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∙ 10y agoWiki User
∙ 10y ago-2
-1 for oxygen in peroxide
Peroxide iion is a anion. O shows the -1 oxidation number.
hydrogen peroxide
6. This is because it is a peroxide, with a structure Cr(O)(O2)2, where the nominal ligands are O2- (-2 ox.number in oxides) and O22- (-1 ox.number in peroxides) which gives the Cr an oxidation number of +6. It is sometimes called Chromium(VI) oxide peroxide.
+1 for each Na -1 for oxygen (as it is peroxide)
-1 for oxygen in peroxide
Peroxide iion is a anion. O shows the -1 oxidation number.
hydrogen peroxide
6. This is because it is a peroxide, with a structure Cr(O)(O2)2, where the nominal ligands are O2- (-2 ox.number in oxides) and O22- (-1 ox.number in peroxides) which gives the Cr an oxidation number of +6. It is sometimes called Chromium(VI) oxide peroxide.
The oxidation number of any free element is 0. So if it is oxygen by itself (e.g., O2) then the oxidation number/state is 0. In its compounds the oxidation number of oxygen is -2. This rule only stands if it isn't a peroxide such as H2O2 or Na2O2, in peroxide cases, the oxygen is -1.
+1 for each Na -1 for oxygen (as it is peroxide)
+1 for each Na -1 for each O (peroxide)
Hydrogen peroxide may be represented as H2O2 or HO-OH, with contrast to normal oxides the oxidation number of oxygen in peroxide is -1.
0 in elemental form +1 in its compounds
Beans
+8.H2 has an oxidation of +1 (A total of +2)O5 has an oxidation of -2 (A total of -10).We do not know anything about the oxidation of S, so since we know H2SO5 isn't a complex ion, we can assume the overall oxidation number is 0.Therefore, the oxidation number of S = Oxidation of O5 - Oxidation number of H2.Since 10 - 2 = 8, Oxidation number of S is 8.(no, it did not)Sorry,Sulphur cannot have more than +6 oxidation number as it belongs to VI(A) group.In H2SO5, one peroxide bond is present. i.e., the oxidation number of 2 oxygen atoms is -2. (Compare hydrogen peroxide, H2O2)2 atoms of oxygen will get -1 oxidation number each. The remaining 3 atoms will have +2 oxidation number each. This is a special case. Oxidation number of each hydrogen atom is +1 only.So, finally the oxidation number of Sulphur is +6. [(+2)+(+6)+(-8) = 0]Hope you got it. (yes, it did so)
The oxidation number (formal charge) on oxygen can be 0, -1/2, -1 or -2. The formal charge on oxygen in a peroxide is -1. Elemental oxygen exists as O2 or O3. The formal charge on all elements is 0. The formal charges on oxygen in an oxide and superoxide, respectively, are -2 and -1/2.