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In NaBr, sodium (Na) has an oxidation number of +1 since it belongs to group 1 of the Periodic Table. Bromine (Br) has an oxidation number of -1 since it is a halogen.

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Formula for sodium bromide?

NaBr When combining a metal with a nonmetal, Name the metal (Sodium), then the stem of the nonmetal + ide (Brom + ide). It is NaBr because Na has an oxidation state of +1 and Br has an oxidation state of also +1 therefore you only need one of each to balance themNaBr


What is the oxidation state of bromine in NaBr?

Well, isn't that a happy little question! In the compound NaBr, bromine has an oxidation state of -1. It's like a little dance between sodium and bromine, creating a balanced and harmonious relationship in the molecule. Just remember, in the world of chemistry, every element has its own special role to play.


__CI2+__NaBr—> __NaCI+__Br2?

2 NaBr (aq) + Cl2 (g) → 2 NaCl (aq) + Br2 (aq) Oxidation reduction reaction 2 Br-I - 2 e- → 2 Br0 (oxidation) 2 Cl0 + 2 e- → 2 Cl-I (reduction) NaBr is a reducing agent, Cl2 is an oxidizing agent.


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