This is a compound. Compounds don't have oxidation numbers, only their constituent elements do. If you must have an answer, use 0.
All you have to do is flip the numbers and reduce. If you have Ca+2 and Br-, Switch the numbers so you get CaBr2. 1 and 2 do not have any common factors so you don't have to reduce! CaBr2 is the final answer.
2Na + Cl2 -> 2NaCl. The oxidation state of the sodium ion in NaCl is +1 and the oxidation state of Chloride ion is -1. Oxidation states of the elemental reactants is zero (as for all elements)
The molecular equation is NaBr (s) + Ca(NO3)2 (aq) -> CaBr2 (s) + 2 NaNO3 (aq). The ionic equation is 2Na+ (aq) + 2NO3- (aq) + Ca2+ (aq) + 2Br- (aq) -> CaBr2 (s) + 2Na+ (aq) + 2NO3- (aq).
A metal typically has only positive oxidation numbers, while a nonmetal can have both positive and negative oxidation numbers. Metals tend to lose electrons (positive oxidation numbers) to form cations, while nonmetals can gain or lose electrons to form a variety of oxidation states.
It shows some oxidation numbers. Generally it shows +4 oxidation numbers.
The only oxidation number is 2+.
In the reaction Ca + Br2 → CaBr2, calcium acts as the reducing agent because it undergoes oxidation by losing electrons to bromine. This results in the formation of calcium bromide (CaBr2).
All you have to do is flip the numbers and reduce. If you have Ca+2 and Br-, Switch the numbers so you get CaBr2. 1 and 2 do not have any common factors so you don't have to reduce! CaBr2 is the final answer.
2Na + Cl2 -> 2NaCl. The oxidation state of the sodium ion in NaCl is +1 and the oxidation state of Chloride ion is -1. Oxidation states of the elemental reactants is zero (as for all elements)
A metal typically has only positive oxidation numbers, while a nonmetal can have both positive and negative oxidation numbers. Metals tend to lose electrons (positive oxidation numbers) to form cations, while nonmetals can gain or lose electrons to form a variety of oxidation states.
It shows some oxidation numbers. Generally it shows +4 oxidation numbers.
No, the can only have positive oxidation numbers
The sum of the oxidation numbers for P2O5 is zero. In P2O5, the oxidation number for phosphorus is +5, and each oxygen atom has an oxidation number of -2. Since there are five oxygen atoms, the total sum of the oxidation numbers is 2(+5) + 5(-2) = 0.
The oxidation numbers in PO43- , phosphorus oxidation number=+5; oxygen = -2
The molecular equation is NaBr (s) + Ca(NO3)2 (aq) -> CaBr2 (s) + 2 NaNO3 (aq). The ionic equation is 2Na+ (aq) + 2NO3- (aq) + Ca2+ (aq) + 2Br- (aq) -> CaBr2 (s) + 2Na+ (aq) + 2NO3- (aq).
The simple answer is not always. The stoicheometry deals with oxidation numbers only in redox reactions. The ratio of the change in oxidation numbers is straightly its stoicheometry.
The sum of the oxidation numbers in a neutral compound is equal to zero. This is because in a neutral compound, the total positive oxidation numbers are balanced by the total negative oxidation numbers to give a net charge of zero.