- log(0.25 M HCl)
= 0.6 pH
------------
The pH of a 6M HCl solution is 0.
- log(0.00450 M HCl)= 2.3 pH=======
The pH of a solution containing 6M HCl is 0.
The pH of water decreases after adding HCl due to the increase in hydrogen ions. The resulting pH level depends on the amount of HCl added.
To prepare 10mL of a 25M HCl solution, you would need to dilute the concentrated HCl solution with the appropriate amount of water. For example, to make a 25M solution, you could start with a 10M HCl solution and dilute it appropriately. To determine the specific volume of each solution needed for dilution, you can use the formula C1V1 = C2V2, where C1 is the initial concentration, V1 is the volume of the initial solution, C2 is the final concentration, and V2 is the final volume.
The pH of a 6M HCl solution is 0.
- log(0.00450 M HCl)= 2.3 pH=======
The pH of a solution containing 6M HCl is 0.
The pH of water decreases after adding HCl due to the increase in hydrogen ions. The resulting pH level depends on the amount of HCl added.
To prepare 10mL of a 25M HCl solution, you would need to dilute the concentrated HCl solution with the appropriate amount of water. For example, to make a 25M solution, you could start with a 10M HCl solution and dilute it appropriately. To determine the specific volume of each solution needed for dilution, you can use the formula C1V1 = C2V2, where C1 is the initial concentration, V1 is the volume of the initial solution, C2 is the final concentration, and V2 is the final volume.
.260 M of HCL, not 260 More than likely correct, but, - log(0.260 M HCl) = 0.6 pH ----------- ( pH can be below 1 )
A 0.1 M concentration of HCl corresponds to a pH of 1.0.
The pH increases because the HCl is becoming less acidic. A pH of 7 is neutral. A pH falls below 7, acidity increases. As pH rises above 7, basicity increases. Diluting HCl means that the HCl becomes less concentrated, and therefore, less acidic. As it becomes less acidic, the pH will become more basic, and thus increase.
Since HCl is a strong acid it completely dissociates. Therefore [H+] = [HCl] and this case = 0.25 M. pH = -log [H+] = 0.602
The pH of a 0.005N HCl solution is approximately 2.3. This is because HCl is a strong acid that dissociates completely in water to form H+ ions, leading to an acidic pH.
0.002M HCl means 0.002 moles HCl in 1L solution. Therefore 0.02 moles HCl in 10L solution. pH = 2-log2 = 2-0.3010 = 1.6990
The pH of 0.05 M HCl is 1.3. HCl is a strong acid that dissociates completely in water to release H+ ions, resulting in a low pH.