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The compound Ba(OH)2·8H2O has 8 water molecules associated with it. To find the percentage of water in the compound, calculate the molar mass of the water molecules (8H2O) and the molar mass of the entire compound (Ba(OH)2·8H2O). Then divide the molar mass of the water by the molar mass of the entire compound and multiply by 100 to get the percentage of water.
Ba(OH)2·8H2O Barium Hydroxide Octahydrate Ba(OH)2·8H2O
Ba(OH)2.8H2O=315.51 8H2O=8x18.02=144.16 ?=144.16/315.51x100=45.69%
The molar mass of BaSO4 is 233.4 g/mol. Therefore, 0.0891 g of BaSO4 corresponds to 0.000382 moles of BaSO4. Since BaSO4 contains 1 mole of Ba for every 1 mole of BaSO4, the original sample contained 0.000382 moles of Ba. The percentage of barium in the compound is calculated as (mass of Ba / total mass of the compound) * 100, which equals approximately 0.143%.
The molar mass of BaSO4 is 233.4 g/mol. From the given data, the number of moles of BaSO4 formed can be calculated as 0.0891 g / 233.4 g/mol = 3.82 x 10^-4 moles. Since 1 mole of BaSO4 contains 1 mole of Ba, the number of moles of Ba in the sample is also 3.82 x 10^-4. The percentage of Ba in the original sample is then (3.82 x 10^-4 moles / molar mass of Ba) x 100%.
Molar mass of all oxygen in compound/Total molar mass of compound * 100 = % oxygen in compound ==================
The compound Ba(OH)2·8H2O has 8 water molecules associated with it. To find the percentage of water in the compound, calculate the molar mass of the water molecules (8H2O) and the molar mass of the entire compound (Ba(OH)2·8H2O). Then divide the molar mass of the water by the molar mass of the entire compound and multiply by 100 to get the percentage of water.
The relative molecular weight of the compound nickel (II) sulphate heptahydrate NiSO4 7H2O is 280. 86. The total mass of oxygen in the compound is 176 g. Therefore the total percentage of oxygen to the nearest tenth is 60 percent
The chemical formula for barium hydroxide octahydrate is Ba(OH)2•8H2O.
Ba(OH)2·8H2O Barium Hydroxide Octahydrate Ba(OH)2·8H2O
Barium hydroxide octahydrate, often written as Ba(OH)2·8H2O, is a chemical compound that consists of one barium ion (Ba2+) and two hydroxide ions (OH-) surrounded by eight water molecules. This compound is commonly used in laboratories as a strong base and in certain industrial processes.
Ba(OH)2.8H2O=315.51 8H2O=8x18.02=144.16 ?=144.16/315.51x100=45.69%
The molar mass of BaSO4 is 233.4 g/mol. Therefore, 0.0891 g of BaSO4 corresponds to 0.000382 moles of BaSO4. Since BaSO4 contains 1 mole of Ba for every 1 mole of BaSO4, the original sample contained 0.000382 moles of Ba. The percentage of barium in the compound is calculated as (mass of Ba / total mass of the compound) * 100, which equals approximately 0.143%.
The molar mass of BaSO4 is 233.4 g/mol. From the given data, the number of moles of BaSO4 formed can be calculated as 0.0891 g / 233.4 g/mol = 3.82 x 10^-4 moles. Since 1 mole of BaSO4 contains 1 mole of Ba, the number of moles of Ba in the sample is also 3.82 x 10^-4. The percentage of Ba in the original sample is then (3.82 x 10^-4 moles / molar mass of Ba) x 100%.
Barium Selenide
There are two oxygen atoms in one unit of the compound Ba(OH)2.
There are two oxygen atoms in one unit of the compound Ba(OH)2.