you have CH3CH2CH2OH (propanol) + HBR = first you alcohol get protnated to good leaving group and to lower base which water . so you have CH3CH2CH2HO+ Br-. Then when water leaves you have final product of CH3CH2CH2Br + HOH.
1. CH3CH2CH3OH +HBR ( What you started with)
2. CH3CH2CH2HOH +Br- ( reaction after protnation of alcohol to good leaving group).
3. CH3CH2CH2BR + HOH ( final product primary haloalkane and water).
The final product is 2-bromo propane.
The reaction is:CH3NH2 + HBr = CH3NH3Br
The reaction is:Sr(OH)2 + 2 HBr = SrBr2 + 2 H2O
Not a chemical reaction but the formation of hydrogen bromide (or hydrobromic acid, HBr) water solution.
i dont think there is any reaction between H2 and HBr.
acid is hbr and the base is h2o
The reaction is:CH3NH2 + HBr = CH3NH3Br
This equation is:HBr + LiOH = LiBr + H2O
The reaction is:Sr(OH)2 + 2 HBr = SrBr2 + 2 H2O
Br2 + H20 ===> HBr + HOBr
Not a chemical reaction but the formation of hydrogen bromide (or hydrobromic acid, HBr) water solution.
i dont think there is any reaction between H2 and HBr.
acid is hbr and the base is h2o
CH4 + Br2 --> CH3Br + HBr
It produces Bromomethane and Hydrogen Bromide Equation: CH4 + Br2 ----> CH3Br + HBr
CH3CH2CH3 + Br2 = CH3CHBrCH3 + HBr The major product formed from the reaction is 2-bromopropane. It is a free radical bromination reaction. It is called a substitution reaction because you are substituting a H an atom for a Br atom and making HBr.
The answer is 770,9 mL solution.
This is a Neutralization reaction. HBr(aq)+CsOH(aq)--->CsBr(aq)+H2O(l)