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Ammonium Nitrate + Water

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What mass of ammonia is consumed by the reaction of g of oxygen gas?

To determine the mass of ammonia consumed, we need the balanced equation for the reaction. Without that information, we cannot accurately calculate the amount of ammonia consumed by the reaction of g of oxygen gas.


What is an ammoxidation?

An ammoxidation is the reaction of ammonia and oxygen with any of several classes of organic compound.


What does ammonia nitrogen and oxygen make?

If you think to burning of ammonia the chemical reaction is:4 NH3 + 3 O2 = 2 N2 + 6 H2O


Why there is no water formation in the neutralisation reaction between ammonia and HCl?

Water is only formed if there is oxygen atom present and in this reaction no oxygen atom is present. Rather than neutralisation it is a combination reaction in which ammonia and HCl combine to produce ammonium chloride.


How many grams of oxygen are needed to react with 23.9 grams of ammonia?

The balanced equation for the reaction between ammonia (NH3) and oxygen (O2) is 4NH3 + 5O2 → 4NO + 6H2O. To find the grams of oxygen needed to react with 23.9 grams of ammonia, you need to calculate the molar ratio between ammonia and oxygen using the balanced equation. Once you find the molar ratio, you can calculate the grams of oxygen required.


Does ammonia burn in oxygen?

Yes, ammonia can burn in the presence of oxygen to form nitrogen dioxide, water, and nitrogen gas as byproducts. This combustion reaction can occur under specific conditions, such as with a high temperature ignition source.


What is the balanced equation for the reaction of ammonia with oxygen with methane to form hydrogen cyanide and water?

The balanced equation for the reaction of ammonia (NH3), oxygen (O2), and methane (CH4) to form hydrogen cyanide (HCN) and water (H2O) is: 4 NH3 + 3 O2 + CH4 → 2 HCN + 6 H2O


Balanced equation for ammonia reacting with oxygen?

The balanced equation for the reaction of ammonia (NH3) with oxygen (O2) to form nitrogen monoxide (NO) and water (H2O) is: 4NH3 + 5O2 → 4NO + 6H2O


How many grams of oxygen are needed to react with 6.78 grams of ammonia?

To calculate the number of grams of oxygen needed to react with 6.78 grams of ammonia, we first write out the balanced chemical equation for the reaction between ammonia (NH3) and oxygen (O2) to form nitrogen monoxide (NO) and water (H2O). Then we use the stoichiometry of the equation to find the molar ratio between ammonia and oxygen. Finally, we convert the mass of ammonia to moles and then use the molar ratio to find the mass of oxygen needed.


What is the formula for ammonia with oxygen to form nitrogen monoxide and water?

A balanced equation for reaction of ammonia with oxygen to form nitrogen monoxide and water is 4 NH3 + 5 O2 -> 4 NO + 6 H2O.


Ammonia mix with Oxygen and ammonia mix with Ozone?

When ammonia mixes with oxygen, it can form nitrogen gas and water through a chemical reaction. On the other hand, when ammonia mixes with ozone, it can react to form nitrogen gas, water, and nitrogen dioxide, which is a harmful air pollutant.


What is the Balanced chemical formula for ammonia oxygen --- dinitrogen oxide water?

The balanced chemical equation for the reaction between ammonia (NH3) and oxygen (O2) to form dinitrogen oxide (N2O) and water (H2O) is: 4NH3 + 5O2 → 4N2O + 6H2O