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The number of moles of oxygen in the reaction vessel is?
To calculate the number of moles of oxygen in the reaction vessel, you need to know the amount of oxygen in grams and its molar mass. Then divide the mass of oxygen by its molar mass to obtain the number of moles. The formula to calculate the number of moles is: moles = mass / molar mass.
What mass of water ts produce?
I am conducting a through ivestigation of the combustion of ammonia gas: 4NH3 + 5O2 > 4NO + 6H2O The reaction will be monitored by the pressure of the gases present in a 5.400 L steel chamber that is at 25.00 degrees C initially but 75 degrees C after the reaction. The chamber is initially filled with 21.250 ATM of oqygen (in slight excess) and an additional 16.500 ATM of ammonia. This one just simply stumps me.
What is the mass difference between water and hydrogen plus oxygen?
The mass of water would be equal to the mass of oxygen plus the mass of hydrogen used in the reaction. The law of the conversation of mass states that in a reaction no mass is either gained or lost. In this case the total amount of mass of the reactants (Oxygen and Hydrogen), according to the law of the conversation of mass, must be equal to the product (water), because no mass can be lost or gained during the reaction.
In a chemical reaction the total mass of the reactants is equal to the mass of the products what is it?
This principle is known as the Law of Conservation of Mass, which states that in a closed system, the total mass remains constant during a chemical reaction. This means that the mass of all reactants consumed in the reaction is equal to the mass of the products formed. This law underscores the idea that matter cannot be created or destroyed, only transformed.
What is the percentage by mass of hydrogen in ammonia?
Mass of ammonia is 17. Mass of Hydrogen in it is 3. So the percentage of hydrogen by mass is 17.64%
How many grams of oxygen are needed to react with 6.78 grams of ammonia?
To calculate the number of grams of oxygen needed to react with 6.78 grams of ammonia, we first write out the balanced chemical equation for the reaction between ammonia (NH3) and oxygen (O2) to form nitrogen monoxide (NO) and water (H2O). Then we use the stoichiometry of the equation to find the molar ratio between ammonia and oxygen. Finally, we convert the mass of ammonia to moles and then use the molar ratio to find the mass of oxygen needed.
Compare the mass of iron and oxygen before the reaction with the mass of rust resulting from the reaction?
The mass of iron plus the mass of oxygen used in the reaction is equal to the mass of rust formed after the reaction.Iron, Fe Relative Atomic Mass = 55.85 g/molOxygen, O Ar = 16.00 g/molRust, Fe2O3 Relative Molar Mass = 2 x 55.85 + 3 x 16.00Mr = 159.7 g/molPercentage of iron by mass = (2 x 55.85)/ 159.7 x 100= 69.94%Percentage oxygen by mass in rust = 30.06%a
The number of moles of oxygen in the reaction vessel is?
To calculate the number of moles of oxygen in the reaction vessel, you need to know the amount of oxygen in grams and its molar mass. Then divide the mass of oxygen by its molar mass to obtain the number of moles. The formula to calculate the number of moles is: moles = mass / molar mass.
What quantities are consumed in a chemical reaction?
Mass is conserved in a chemical reaction, but the coefficient attached to the reactants may be different than the products.
How does combining hydrogen and oxygen to create water relate to the law of conservation of mass?
When hydrogen and oxygen combine to form water, the total mass of the reactants before the reaction is equal to the total mass of the products after the reaction. This demonstrates the law of conservation of mass, which states that mass is neither created nor destroyed in a chemical reaction, only rearranged.
How many grams of ammonia NH3 will be prepared when 6.00g of hydrogen H2 has reacted?
The reaction between hydrogen and ammonia to form ammonia is 3H2 + N2 → 2NH3. To find the amount of ammonia produced when 6.00g of hydrogen reacts, first convert the mass of hydrogen to moles using its molar mass. Then, use the mole ratio from the balanced equation to find the moles of ammonia produced, and finally, convert this to grams using the molar mass of ammonia.
If 250.3 L of hydrogen gas (d 0.0899gL ) reacts with an excess of nitrogen gas what mass of ammonia would be produced?
To determine the mass of ammonia produced, you first need to calculate the moles of hydrogen gas present. Then, you can use the stoichiometry of the balanced chemical equation for the reaction between hydrogen and nitrogen to find the moles of ammonia produced. Finally, using the molar mass of ammonia, you can convert moles to grams to find the mass of ammonia produced.
What law of mass describes when mass of products and reactants is equal?
The law of conservation of mass states that mass is neither created nor destroyed in a chemical reaction. This means that the total mass of the products formed in a reaction must equal the total mass of the reactants consumed.
What is the mass percentage of nitrogen in ammonia?
The mass percentage of nitrogen in ammonia (NH3) is 82.35%. This is calculated by dividing the mass of nitrogen in one mole of ammonia by the molar mass of ammonia, and then multiplying by 100 to get the percentage.
What mass of ammonia is formed when 3.80 g of nitrogen gas react with hydrogen?
To calculate the mass of ammonia formed, first write out the balanced chemical equation for the reaction between nitrogen and hydrogen to form ammonia: N₂ + 3H₂ → 2NH₃ Next, calculate the moles of nitrogen in 3.80 g using the molar mass of nitrogen (N₂). Then use the mole ratio from the balanced equation to determine the moles of ammonia formed. Finally, convert the moles of ammonia to grams using the molar mass of ammonia (NH₃) to find the mass formed.
Nitrogen and hydrogen react to form ammonia. If you react 45 g of nitrogen with 30 g of hydrogen, what will the mass be at the end Include unites?
The balanced chemical equation for the reaction is N2 + 3H2 → 2NH3. The molar mass of nitrogen is 14 g/mol and hydrogen is 2 g/mol. One mole of N2 reacts with three moles of H2 to produce two moles of NH3. Therefore, the mass of ammonia produced will be 45 g of N2 + 30 g of H2 = 75 g, as both reactants are fully consumed in the reaction.
Why is a mass bigger if magnesium is burned in oxygen?
When magnesium is burned in oxygen, it undergoes a chemical reaction called combustion. During this reaction, magnesium atoms combine with oxygen atoms to form magnesium oxide. The increased mass observed after burning magnesium is due to the formation of magnesium oxide, which adds the combined mass of magnesium and oxygen atoms to the initial mass of the magnesium.
