When sulphite reacts with lead acetate, it forms lead sulphite and lead acetate. The balanced chemical equation for this reaction is: Pb(CH3COO)2 + SO3^2- -> PbSO3 + 2CH3COO-
When copper II acetate reacts with sodium sulfide, they undergo a double displacement reaction where the cations and anions switch partners. This results in the formation of copper II sulfide and sodium acetate as the products. Balanced chemical equation for this reaction is Cu(CH3COO)2 + Na2S —> CuS + 2CH3COONa.
Acetic acid reacts with a base to form water and a salt called sodium acetate. This reaction is a neutralization reaction where the hydrogen ion from the acid combines with the hydroxide ion from the base to form water.
The reaction between 3-methyl-1-butanol and glacial acetic acid is an esterification reaction, producing the ester 3-methylbutyl acetate. This reaction is typically catalyzed by an acid, such as sulfuric acid. Water is produced as a byproduct during this reaction.
This is a double displacement or metathesis reaction, where the positive ions in the reactants switch places to form new compounds. In this case, zinc acetate reacts with sodium sulfide to form zinc sulfide (a solid precipitate) and sodium acetate.
The reaction of 1-butanol with acetic anhydride typically produces an ester, such as butyl acetate. Butyl acetate has a fruity smell, resembling apples or bananas.
The formula for lead (II) acetate is Pb(C2H3O2)2. The formula for sodium iodide is NaI. When lead acetate reacts with sodium iodide, the double displacement reaction forms lead (II) iodide (PbI2) and sodium acetate (NaC2H3O2).
Sodium Iodide is the solute which is created in the reaction and Sodium actetate solution is created. NaI + PbC2H3O2 ---> PbI (Plumbum Iodide) + NaC2H3O2 (Sodium Acetate) solution.
When copper II acetate reacts with sodium sulfide, they undergo a double displacement reaction where the cations and anions switch partners. This results in the formation of copper II sulfide and sodium acetate as the products. Balanced chemical equation for this reaction is Cu(CH3COO)2 + Na2S —> CuS + 2CH3COONa.
Acetic acid reacts with a base to form water and a salt called sodium acetate. This reaction is a neutralization reaction where the hydrogen ion from the acid combines with the hydroxide ion from the base to form water.
The reaction between 3-methyl-1-butanol and glacial acetic acid is an esterification reaction, producing the ester 3-methylbutyl acetate. This reaction is typically catalyzed by an acid, such as sulfuric acid. Water is produced as a byproduct during this reaction.
This is a double displacement or metathesis reaction, where the positive ions in the reactants switch places to form new compounds. In this case, zinc acetate reacts with sodium sulfide to form zinc sulfide (a solid precipitate) and sodium acetate.
The reaction between sodium acetate and water is a dissolution process where sodium acetate dissociates into its ions (sodium and acetate) when placed in water. The equation for this process is: CH3COONa + H2O → CH3COO- + Na+ + H2O
The reaction of 1-butanol with acetic anhydride typically produces an ester, such as butyl acetate. Butyl acetate has a fruity smell, resembling apples or bananas.
when 8-hydroxyquinoline and aluminum reacts a yellow ppt is formed( aluminum-8-hydroxyquinolate) .....but bot sure bout d ammonium acetate. I kno the ammonium acetate helps the helps the precipitate to form.....hope someone can fill the blanks...
When a strong acid reacts with a metal acetate, it typically forms the corresponding metal salt and acetic acid. For example, if hydrochloric acid reacts with sodium acetate, it would produce sodium chloride and acetic acid. This reaction involves the displacement of the anion of the acid by the acetate anion.
When pure barium is added to a solution of silver acetate, a double displacement reaction occurs. Barium acetate and silver metal are formed as products. Additionally, barium sulfate may also form if sulfate ions are present in the solution.
solid