-1.68 V
3Ag2S + 2Al(s) ==> Al2S3 + 6 Ag(s)Ag^+ + e- ===> Ag(s) reduction @ cathode Eº=0.80 VAl ===> Al^3+ + 3e- oxidation @ anode Eº=-1.66 VOverall potential = Eºcell = 0.80 - (-1.66) = 2.46 V
The chemical formula for Al3 is Al3+ which represents an aluminum ion with a charge of +3. The chemical formula for CH3COO is C2H3O2-, which represents the acetate ion.
Al | Al^3+ Zn^2+ | Zn
The compound formed between Al3+ and I- ions is aluminum iodide.
The formula for aluminum oxide is Al2O3: Molar mass =581.77g/mol Al2O3.In one mole Al2O3, there are two moles of Al3+ ions, therefore 2 moles Al3+ x 26.982g/mol Al3+ = 53.964g Al3+ in one mole of Al2O3.GIVEN: mass of Al3+ = 53.964 g Al3+;Molar mass of Al2O3 = 581.77 g Al2O3UNKNOWN: % Al3+EQUATION:% Al3+...=...g Al3+x 100...g Al2O3% Al3+...=...53.964g Al3+x100......=...9.2758% Al3+581.77g Al2O3
-1.68 V
-1.68
-1.68 V
- .92 V
3Ag2S + 2Al(s) ==> Al2S3 + 6 Ag(s)Ag^+ + e- ===> Ag(s) reduction @ cathode Eº=0.80 VAl ===> Al^3+ + 3e- oxidation @ anode Eº=-1.66 VOverall potential = Eºcell = 0.80 - (-1.66) = 2.46 V
The chemical formula for Al3 is Al3+ which represents an aluminum ion with a charge of +3. The chemical formula for CH3COO is C2H3O2-, which represents the acetate ion.
Al3 - Aluminum cationCN-Cyanide ion
Al | Al^3+ Zn^2+ | Zn
Au(s) | Au+(aq) Al3+(aq) | Al(s)(-_^)
Al(s) | Al3+(aq) Ni2+(aq) | Ni(s)
The compound formed between Al3+ and I- ions is aluminum iodide.
Type your answer here... Al(s) | Al3+(aq) Mg2+ (aq) | Mg(s)