3Ag2S + 2Al(s) ==> Al2S3 + 6 Ag(s)
Ag^+ + e- ===> Ag(s) reduction @ cathode Eº=0.80 V
Al ===> Al^3+ + 3e- oxidation @ anode Eº=-1.66 V
Overall potential = Eºcell = 0.80 - (-1.66) = 2.46 V
Each molecule of Al2S3 is composed of one Al3+ ion. Since a mole is equal to 6.022 x 1023 molecules, there would be 6.022 x 1023 Al3+ ions in one mole of Al2S3.
The balanced chemical equation for the reaction between Al2S3 and H2O to produce H2S is: Al2S3 + 6 H2O -> 2 Al(OH)3 + 3 H2S From the balanced equation, 1 mol of Al2S3 produces 3 mol of H2S. Therefore, if 4.0 mol of Al2S3 is reacted, the theoretical yield of H2S would be 3 * 4.0 mol = 12.0 mol.
Barium is a more active metal than aluminium. In fact, the lower elements in the activity series gains electrons from the higher elements, which are also called as displacement reactions. The final products of this reaction would be barium sulfide and aluminium metal.
The water potential is really just the sum of the pressure potential and the solute potential. Obviously, then, lower pressure potential would lower the water potential, and so would lower solute potential. To lower the solute potential, the moles of the solute would actually have to increase. This probably seems backwards, but the equation for solute potential is -iCRT (where C is moles/liter, for some reason). Because there's a negative sign, the more moles you have, the less the solute potential is. Hopefully that helps.
The addition of solutes decreases the water potential of a solution. This is because the presence of solutes reduces the free water molecules available to participate in osmotic processes, resulting in a lower overall potential for water movement.
Each molecule of Al2S3 is composed of one Al3+ ion. Since a mole is equal to 6.022 x 1023 molecules, there would be 6.022 x 1023 Al3+ ions in one mole of Al2S3.
The balanced chemical equation for the reaction between Al2S3 and H2O to produce H2S is: Al2S3 + 6 H2O -> 2 Al(OH)3 + 3 H2S From the balanced equation, 1 mol of Al2S3 produces 3 mol of H2S. Therefore, if 4.0 mol of Al2S3 is reacted, the theoretical yield of H2S would be 3 * 4.0 mol = 12.0 mol.
DNA sequencing can identify genes that have the potential to cause you health problems. Knowing your DNA sequence could help your overall health in that you would know where potential problems may be. For example, if your sequence shows a potential for diabetes, living a life style that would help prevent diabetes would be helpful.
Reacted aluminum has a +3 charge. Sulfur is usually a -2 charge. Thus the equation would be 2 Al + 3 S --> Al2S3
The water potential is really just the sum of the pressure potential and the solute potential. Obviously, then, lower pressure potential would lower the water potential, and so would lower solute potential. To lower the solute potential, the moles of the solute would actually have to increase. This probably seems backwards, but the equation for solute potential is -iCRT (where C is moles/liter, for some reason). Because there's a negative sign, the more moles you have, the less the solute potential is. Hopefully that helps.
Barium is a more active metal than aluminium. In fact, the lower elements in the activity series gains electrons from the higher elements, which are also called as displacement reactions. The final products of this reaction would be barium sulfide and aluminium metal.
The addition of solutes decreases the water potential of a solution. This is because the presence of solutes reduces the free water molecules available to participate in osmotic processes, resulting in a lower overall potential for water movement.
The standard reduction potentials for Mg/Mg^2+ and Cu^2+/Cu are -2.37 V and +0.34 V, respectively. To determine the overall cell potential, you subtract the reduction potential of the anode (Mg/Mg^2+) from the reduction potential of the cathode (Cu^2+/Cu) since the anode is where oxidation occurs. Therefore, the overall cell potential would be 0.34 V - (-2.37 V) = 2.71 V.
To covalently bond aluminum and sulfur, you would need to have aluminum sulfide (Al2S3) formed through a chemical reaction. This can be achieved by heating a mixture of aluminum powder and sulfur in a controlled environment to allow the formation of covalent bonds between aluminum and sulfur atoms.
Two aluminum atoms and three sulfur atoms would have the formula Al2S3. When writing a formula for an ionic compound, the positive ion (in this case Al3+) is written first. Very often, an ionic compound is composed of a metal and a nonmetal, as in Al2S3, in which case the metal ion will be written first because it will always be positively charged.
The pressure potential of a flaccid cell would be low or close to zero. Flaccid cells have lost water and are not turgid, so the pressure potential, which is related to the water pressure inside the cell, would be minimal.
4.2 V