Both volume (V) and quantity (n) of the gas have to be known to calculate, not only the pressure by Gas Law:
p . V = n . T . (R)
in which (R) is the general 'gas constante': 8.3145 (J/mol.K)
39.0
1 atm of pressure equals 760 mm Hg, so 2 atm = 1520 mm Hg.
If the total (=atmospheric) gas pressure is 760 mm Hg, then the remaining partial pressure of 760 - (630 + 39) = 91 mm of Hg is for the 3rd gas in blood: Oxygen (O2)
the answer is 72.1 Hg
22.3 L
375mmhg
39.0
7.41 L
190 mm Hg
13.7, using P1V1T2=P2V2T1.
1 atm of pressure equals 760 mm Hg, so 2 atm = 1520 mm Hg.
To convert Torr to mm Hg, divide by 1.33. So, the partial pressure of helium in mm Hg is 439 Torr / 1.33 = 330 mm Hg. To find the partial pressure of hydrogen, subtract the partial pressure of helium from the total pressure: 600 mm Hg - 330 mm Hg = 270 mm Hg. Hence, the partial pressure of hydrogen gas is 270 mm Hg.
If the total (=atmospheric) gas pressure is 760 mm Hg, then the remaining partial pressure of 760 - (630 + 39) = 91 mm of Hg is for the 3rd gas in blood: Oxygen (O2)
161 mm Hg.
The phrase "760 mm Hg" is physicists' shorthand for "an atmospheric pressure equal to that needed to support a column of mercury [chemical symbol Hg] of length 760 mm". This is approximately average atmospheric pressure at sea level. As the pressure decreases from "760 mm Hg" to "350 mm Hg", the volume of the gas will increase (assuming a constant temperature). The new volume can be determined using Boyle's Law: New Volume = 30 x 760 / 350 = 65.143 Litres
This cannot be answered without an initial volume or pressure. But the final pressure of an expansion of a gas can be determined by the following formula. PV/T = P'V'/T' where P = pressure absolute V = volume T = temperature absolute ( ' ) indicates the new pressure, volume and temperature because the temperature is constant this can be reduced to PV = P'V' or P' = PV/V'
pressure in kilopascals = 3.38639 x (pressure in Hg/10) = 274.636229 kpa ~274.64 kpa