Hello
18 g
4
4.50gramH20
The maximum amount of product that can be formed is found by first writing out the balanced equation for the reaction. Calculate the number of moles of starting material you have (moles = mass/molar mass) Use the equation to figure out how many moles of product this will produce. Convert this to grams by multiplying by the mole mass (of the new substance this time.)
96.75 grams of NaCl
Fe2O3 (s) + 3 CO (g) 🡪 2 Fe (s) + 3 CO2 (g) Calculate the number of grams of CO that can react with 250 g of Fe2O3. Calculate the number of grams of Fe and the number of grams of CO2 formed when 250 grams of Fe2O3 reacts.
4
4.50gramH20
5a+10b = 10ab
The maximum amount of product that can be formed is found by first writing out the balanced equation for the reaction. Calculate the number of moles of starting material you have (moles = mass/molar mass) Use the equation to figure out how many moles of product this will produce. Convert this to grams by multiplying by the mole mass (of the new substance this time.)
96.75 grams of NaCl
322 grams.
mass of CaF3 = 61.96g mass of Al2CO3 =61.104 g
One kilogram is equal to 1,000 grams. The number of grams in one million kilograms would be the product of 1,000,000 multiplied by 1,000.
Fe2O3 (s) + 3 CO (g) 🡪 2 Fe (s) + 3 CO2 (g) Calculate the number of grams of CO that can react with 250 g of Fe2O3. Calculate the number of grams of Fe and the number of grams of CO2 formed when 250 grams of Fe2O3 reacts.
You need to be more specific, but in general if 22.4g react completely then 22.4g are formed.
The answer is o,5 mol.
there would be 50 grams of ammonia will be formed