valence electron are the electrons in the atoms outer most orbit making themselves avalible for bonding and different chemical interactions. a quick check to figure out how many valence electrons are present is to look at a Periodic Table, pick and element and elemental positions back to group one (excluding the transition metals. for example, N has 5 valence electrons carbon has 4 F has 7
note: when we say N has a valence of 3 its because 2 of the valence electrons are found in a pair leaving 3 electrons available for bonding. so N has 5 valence electrons and a "valence" of 3
Silicon has three orbitals in its valence shell: one 3s orbital and two 3p orbitals. This gives it a total of four valence electrons.
Thus the total number of atomic orbitals in the fourth energy level of an atom is 16.
Nitrogen has 5 valence electrons. Its atomic number is 7 therefore it has a total of 7 electrons. If you put this in a Bohr-Rutherford Diagram, there would be 2 electrons in the first shell (Helium structure) and 5 electrons in the outer shell. The number of electrons in an element's outermost shell is its number of valence electrons.
Oxygen, because it only has four orbitals in its valence shell to accomodate extra electrons.
Valence electrons are the total amount of electrons on the outermost shell of an atom. Meaning if the last shell has two, the valence electrons are two. But a complete valence shell would hold eight.
Silicon has three orbitals in its valence shell: one 3s orbital and two 3p orbitals. This gives it a total of four valence electrons.
Thus the total number of atomic orbitals in the fourth energy level of an atom is 16.
The shell that contains a total of 9 orbitals is the third shell. This shell consists of one 3s orbital, three 3p orbitals, and five 3d orbitals, which adds up to 9 orbitals in total.
Each shell has a total of n2 orbitals, where n is the principal quantum number. For N shells the total orbitals is therefore :- N2 + (N-1)2 + (N-2)2 +....+1
Nitrogen has 5 valence electrons. Its atomic number is 7 therefore it has a total of 7 electrons. If you put this in a Bohr-Rutherford Diagram, there would be 2 electrons in the first shell (Helium structure) and 5 electrons in the outer shell. The number of electrons in an element's outermost shell is its number of valence electrons.
If the question is an attempt to ask "How many orbitals are there with principal quantum number n = 2", then 4 orbitals which can hold a total of 8 electrons.
no. just the valence shell
Oxygen, because it only has four orbitals in its valence shell to accomodate extra electrons.
There are three p orbitals in all levels 2 and above. these are the px, py and pz orbitals, the (suffix is the direction - px lies along the x axis). In the 5th level they will be 5px, 5py, 5pz
An atom of fluorine has 9 electrons in total. Electrons are equal to protons when the atom isn't an ion, and the number of protons is also the atomic number of the element, so you just need to know the atomic number to find out the number of electrons or protons.
There is no simple answer to your question, as your question is too broad and undefined. For simple atoms, the number of valence electrons is the number of electrons in unfilled electron shells, which are then available for bonding to another atom. Oxygen with 8 total electrons has 6 paired electrons in filled electron orbitals, and 2 valence electrons in unfilled orbitals. That is why it forms bonds with 2 hydrogen molecules to form water (H2O) The number of valence electrons can change when you add or remove electrons from an atom, or in more complex atoms where filled orbitals to unfilled orbitals have the same energy and electrons can move from one to another depending on the number of other atoms it is binding with.
Sulphur has 16 electrons. Correction: there is 16 in total, but 6 in the outer (valence) shell.