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What mass of chlorine gas will react with 92 grams of sodium?
The balanced chemical equation for the reaction between chlorine gas and sodium is: 2Na + Cl2 -> 2NaCl Using the equation, we can see that 1 mole of chlorine gas (Cl2) reacts with 2 moles of sodium (2Na). To calculate the mass of chlorine gas needed to react with 92 grams of sodium, first convert 92 grams of sodium to moles, then use the mole ratio from the balanced equation to find the moles of chlorine gas needed. Finally, convert the moles of chlorine gas to grams.
How many grams of chlorine gas are required to react completely with 2.00 mol of sodium?
Sodium reacts with chlorine gas in a 1:1 molar ratio. Thus, for 2.00 mol of sodium, 2.00 mol of chlorine gas is required. The molar mass of chlorine gas is approximately 70.91 g/mol. Therefore, the mass of chlorine gas needed is 2.00 mol x 70.91 g/mol = 141.82 grams.
How many grams of Chlorine are in 7 grams of Sodium Chloride?
To find the answer, we multiply the 7 grams of NaCl by the ratio of the molar mass of chlorine over the molar mass of sodium chloride. By doing this, we find that there are about 4.25 grams of chlorine in 7 grams of NaCl.
Does 14 percent sodium hypochlorite mean 14 percent sodium hypochlorite mass per weight concentration or 14 percent chlorine gas mass per weight concentration equivalent of the solution?
It means 14% of the molecules of the sodium Hypochlorite solution contain the "free-chlorine" required to actually do the desired job of the Hypochlorite. Effectively, only 14% of the mass or moles of the Hypochlorite will react.
What mass of sodium chloride is formed if 22.99 grams of sodium combines with 35.54 grams of chlorine?
The molar mass of sodium chloride is 58.44 g/mol. To find the mass of sodium chloride formed, you need to compare the moles of sodium and chlorine to determine the limiting reactant. Calculate moles of sodium and chlorine, determine limiting reactant, and use stoichiometry to find mass of sodium chloride formed.
How do you make sodium chloride from its elements?
The percentage of sodium in sodium chloride is 39,665 83 %. Mass of NaCl = Mass of sodium X 2,51
A flask is weighed and has a mass of 50.0 grams Then 2.0 grams of sodium metal is added to the flask Chlorine gas is pumped into the flask This allows the sodium metal to react completely with c?
The sodium metal will react with chlorine gas to form sodium chloride. The reaction involves a single displacement reaction where sodium replaces chlorine in its diatomic form to form NaCl. The final mass of the flask will increase by 2.0 grams due to the formation of sodium chloride.
What mass of chlorine gas will react with 92 grams of sodium?
The balanced chemical equation for the reaction between chlorine gas and sodium is: 2Na + Cl2 -> 2NaCl Using the equation, we can see that 1 mole of chlorine gas (Cl2) reacts with 2 moles of sodium (2Na). To calculate the mass of chlorine gas needed to react with 92 grams of sodium, first convert 92 grams of sodium to moles, then use the mole ratio from the balanced equation to find the moles of chlorine gas needed. Finally, convert the moles of chlorine gas to grams.
What is the mass ratio of Na to Cl in sodium chloride?
The ratio mass of chlorine/mass of sodium is 1,5.
How many grams of chlorine gas are required to react completely with 2.00 mol of sodium?
Sodium reacts with chlorine gas in a 1:1 molar ratio. Thus, for 2.00 mol of sodium, 2.00 mol of chlorine gas is required. The molar mass of chlorine gas is approximately 70.91 g/mol. Therefore, the mass of chlorine gas needed is 2.00 mol x 70.91 g/mol = 141.82 grams.
What is the percent composition of chlorine in salt?
By atoms it is 50% sodium and 50% chlorine. By mass (sodium is 23.0, chlorine is 35.5, salt is 58.5) is 39.3% sodium and 60.7% chlorine.
How many grams of Chlorine are in 7 grams of Sodium Chloride?
To find the answer, we multiply the 7 grams of NaCl by the ratio of the molar mass of chlorine over the molar mass of sodium chloride. By doing this, we find that there are about 4.25 grams of chlorine in 7 grams of NaCl.
Does 14 percent sodium hypochlorite mean 14 percent sodium hypochlorite mass per weight concentration or 14 percent chlorine gas mass per weight concentration equivalent of the solution?
It means 14% of the molecules of the sodium Hypochlorite solution contain the "free-chlorine" required to actually do the desired job of the Hypochlorite. Effectively, only 14% of the mass or moles of the Hypochlorite will react.
What mass of chlorine gas will react with 92.0 of sodium?
The equation for the reaction between sodium and chlorine is 2 Na + Cl2 -> 2 NaCl. This equation shows that equal numbers of formula units of sodium and chlorine are changed during the reaction. The gram Atomic Mass of two sodium atoms is 2 [exact] X 22.9898 or45.9796. therefore the specified amount of sodium is 92.0/45.9796 or 2.00 double gram atoms, to the justified number of significant digits. Therefore 2.00 double gram atoms of chlorine are required. The gram atomic mass of chlorine is 35.453, and four times this amount, or 142 grams of chlorine, to the justified number of significant digits, are needed for complete reaction.
What mass of sodium chloride is formed if 22.99 grams of sodium combines with 35.54 grams of chlorine?
The molar mass of sodium chloride is 58.44 g/mol. To find the mass of sodium chloride formed, you need to compare the moles of sodium and chlorine to determine the limiting reactant. Calculate moles of sodium and chlorine, determine limiting reactant, and use stoichiometry to find mass of sodium chloride formed.
Calculate the mass of chlorine that can be formed from 50g of sodium chloride?
50 g sodium chloride (NaCl) contain 30,167 g chlorine.
Is 43.98 g of sodium combines with an excess of chlorine gas to form 116.89 g of sodium chloride what mass of chlorine gas is used in this reaction?
To determine the mass of chlorine gas used in the reaction, we can use the law of conservation of mass, which states that the mass of the reactants equals the mass of the products. The mass of sodium chloride (NaCl) formed is 116.89 g, and the mass of sodium (Na) used is 43.98 g. Therefore, the mass of chlorine gas (Cl₂) that reacted can be calculated as follows: Mass of Cl₂ = Mass of NaCl - Mass of Na = 116.89 g - 43.98 g = 72.91 g. Thus, 72.91 g of chlorine gas was used in the reaction.
