yeast
When yeast is deprived of oxygen, it will convert glucose into ethanol and carbon dioxide through a process called fermentation.
To find the molarity, first calculate the number of moles of glucose in 40 g using its molar mass. Then, divide the moles of glucose by the volume of the solution in liters (1.5 L) to get the molarity.
The pH of a solution of C6H12O6 (glucose) is neutral at pH 7 since it does not directly contribute to H+ ions in solution.
To find the molality of a solution, you need the mass of the solvent (usually water) in kilograms and the number of moles of solute (glucose). Given that the solution is 7.80% glucose by weight, you can calculate the mass of glucose in the solution and then convert it to moles using the molar mass of glucose. From there, you can find the molality by dividing the moles of glucose by the mass of the solvent in kilograms.
A solution of ethylene glycol would have the highest freezing point among the three options.
When yeast is deprived of oxygen, it will convert glucose into ethanol and carbon dioxide through a process called fermentation.
To find the molarity, first calculate the number of moles of glucose in 40 g using its molar mass. Then, divide the moles of glucose by the volume of the solution in liters (1.5 L) to get the molarity.
The pH of a solution of C6H12O6 (glucose) is neutral at pH 7 since it does not directly contribute to H+ ions in solution.
It is not an electrolyte as such. It needs to have salts in it that conduct electricity in order to be a complete electrolyte.
Glucose favors the ring form in aqueous solution due to the formation of intramolecular hydrogen bonds between the hydroxyl groups on its carbon atoms. This stabilization of the ring form by hydrogen bonding makes it the more energetically favorable conformation in water.
1kg of glucose produce 0.5kg of ethanol
To find the molality of a solution, you need the mass of the solvent (usually water) in kilograms and the number of moles of solute (glucose). Given that the solution is 7.80% glucose by weight, you can calculate the mass of glucose in the solution and then convert it to moles using the molar mass of glucose. From there, you can find the molality by dividing the moles of glucose by the mass of the solvent in kilograms.
A solution of ethylene glycol would have the highest freezing point among the three options.
do you go to UTAS? that is not an answer how is this going to help people ????
To form ethanol, the chemical equation shows that one mole of glucose is converted to two moles of ethanol. The molar mass of glucose is around 180 g/mol and that of ethanol is around 46 g/mol. Therefore, to produce 127g of ethanol, you would need 127g/(46g/mol) = 2.76 moles of ethanol. Since glucose to ethanol is a 1:2 ratio, you would need half as many moles of glucose, which would be 1.38 moles of glucose.
C6H12O6 (180.16 g/ mol) ---> 2C2H5OH (46.07 g/mol) + 2 CO2 600.4 g glucose @ 92.14 g ethanol / 180.16 g glucose = 307.06 grams of ethanol can be produced 307.06 grams of ethanol @ 0.789g/ml = 389.2 millilitres ========= your answers: 307 grams of ethanol & 0.389 litres of ethanol
Glucose is soluble in ethanol.