Br with six dots
br w/ 6 dots c br w/ six dots
Br with six dots
sorry its kind of hard to type!:)
No, CBr4 and H2O will not form a homogeneous solution. CBr4 is a nonpolar compound, while H2O is polar. Due to the significant difference in polarity, they will not mix evenly to form a homogeneous solution.
Yes
To find the number of molecules in 325g of CBr4, first calculate the number of moles using the molar mass of CBr4 (331.63 g/mol). Then, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules. So, 325g of CBr4 is equal to about 0.981 moles, which is approximately 5.91 x 10^23 molecules.
No, tetrabromomethane (CBr4) is a covalent compound, not ionic. It is composed of nonmetal elements (carbon and bromine) that share electrons to form covalent bonds.
Yes it is molecular (or covalent) compound
Tetrahedral
CBr4 , this is the correct formula for carbon-tetra-bromide
No, CBr4 and H2O will not form a homogeneous solution. CBr4 is a nonpolar compound, while H2O is polar. Due to the significant difference in polarity, they will not mix evenly to form a homogeneous solution.
The electron geometry of CBr4 (carbon tetrabromide) is tetrahedral. This is due to the central carbon atom being bonded to four bromine atoms, which results in four regions of electron density around the carbon. The arrangement minimizes repulsion between these regions, leading to the tetrahedral shape.
Yes
CBr4
To find the number of molecules in 325g of CBr4, first calculate the number of moles using the molar mass of CBr4 (331.63 g/mol). Then, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules. So, 325g of CBr4 is equal to about 0.981 moles, which is approximately 5.91 x 10^23 molecules.
Carbon and bromine can combine to form carbon tetrabromide. Its chemical formula is CBr4.
Carbon Tetrabromide - or tetrabromomethane
1
The molecular mass of CBr4 is 12.0 + 4(79.9) = 331.6Amount of CBr4 = mass of substance / molecular mass = 393/331.6 = 1.19mol This means that a 393g pure sample contains 1.19 moles of tetrabromomethane. The Avogadro's number is 6.02 x 10^23 So, number of molecules of CBr4 = 1.19 x 6.02 x 10^23 = 7.13 x 10^23
CBr4