Br is replaced by Cl.NaCl and Br2 is produced.
Assuming you mean 2NaBr + Cl2 --> 2NaCl + Br2, that's a single replacement reaction.
Yes,they do react.Mainly they form NCl3+HCl or NH4Cl+HCl
Cl2 + 2NaBr => Br2 + 2NaCl One mole Cl2 reacts with 2 moles NaBr Cl2 = 71 NaBr = 102.9 Molar volume = 22.414 L/mole for ideal gas @STP 3L Cl2 = 3/22.414 = 0.1338 mole 25g NaBr = 25/102.9 = 0.2430 mole 0.1338 moles Cl2 requires 0.2676 moles NaBr for complete reaction The NaBr is the limiting reagent
C6H12 + Cl2 --> C6H12Cl2
Redox reaction.
This reaction is 2 Al (s) + 3 Cl2 (g) => 2 AlCl3 (s).
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reaction of NaBr+Cl2
single replacement
Cl2 + 2NaBr => Br2 + 2NaCl One mole Cl2 reacts with 2 moles NaBr Cl2 = 71 NaBr = 102.9 Molar volume = 22.414 L/mole for ideal gas @STP 3L Cl2 = 3/22.414 = 0.1338 mole 25g NaBr = 25/102.9 = 0.2430 mole 0.1338 moles Cl2 requires 0.2676 moles NaBr for complete reaction The NaBr is the limiting reagent
Combination Reaction
C6H12 + Cl2 --> C6H12Cl2
2 NaBr (aq) + Cl2 (g) β 2 NaCl (aq) + Br2 (aq) Oxidation reduction reaction 2 Br-I - 2 e- β 2 Br0 (oxidation) 2 Cl0 + 2 e- β 2 Cl-I (reduction) NaBr is a reducing agent, Cl2 is an oxidizing agent.
It is not possible.
MgBr2 + Cl2 yields MgCl2 + Br2 is an example of an anionic single replacement chemical reaction.
That is a balanced oxidation-reduction reaction. Hydrogen is oxidized, while chlorine is reduced.
Redox reaction.
This chemical reaction is:CS2 + 3 Cl2 = CCl4 + S2Cl2
This is most often called a "single displacement" reaction.