The reaction CCl4 + 2Cl2 → C + 2CCl2 is a redox reaction, specifically a displacement reaction where CCl4 is being reduced to C and Cl2 is being oxidized to CCl2.
H2 + Cl2 --> 2HCl Think of it like this. H2 begins with two electrons, Cl2 begins with 14 (it is diatomic and originally has 7 electrons, so 7 + 7 = 14). The reducing agent is the one being oxidized (you need to remember that!) and if something is being oxidized, it is going from having more electrons to less electrons. 2HCl has 16 electrons (where H has two and Cl has fourteen), so, unless there is a charge on any of these compounds that you did not include in your question, no, Cl is not the reducing agent.
least polar C-S in CS2 C-CL in CCl4 C-O in OCH2 S-F in SF4 most polar
Divide the Molar Mass of C and Cl4 by 56 to get your awnswer!
CCl4 features all single covalent bonds, so the hybridization is sp3.
NH3 is more polar than CCl4. This is because NH3 has a higher electronegativity difference between nitrogen and hydrogen atoms, leading to a greater dipole moment. In contrast, in CCl4, the symmetry of the tetrahedral molecule cancels out the individual dipole moments of the polar C-Cl bonds, resulting in a nonpolar molecule.
C + 2Cl2 ==> CCl4atoms of C needed = 2.00 mol Cl2 x 1 mole C/2 mole Cl2 x 6.02x10^23 atoms/mole = 6.02x10^23 atoms
H2 + Cl2 --> 2HCl Think of it like this. H2 begins with two electrons, Cl2 begins with 14 (it is diatomic and originally has 7 electrons, so 7 + 7 = 14). The reducing agent is the one being oxidized (you need to remember that!) and if something is being oxidized, it is going from having more electrons to less electrons. 2HCl has 16 electrons (where H has two and Cl has fourteen), so, unless there is a charge on any of these compounds that you did not include in your question, no, Cl is not the reducing agent.
Balanced equation. C + 2Cl2 -> CCl4 10 grams carbon (1 mole C/12.01 grams)(1 mole CCl4/1 mole C)(153.81 grams/1 mole CCl4) 128 grams carbon tetrachloride produced -----------------------------------------------------
least polar C-S in CS2 C-CL in CCl4 C-O in OCH2 S-F in SF4 most polar
Divide the Molar Mass of C and Cl4 by 56 to get your awnswer!
CCl4 features all single covalent bonds, so the hybridization is sp3.
Synthesis E + C > C E + E > C
The type of reaction is transmutation .(thanks for reading it )
.Ab + c cb + a
NH3 is more polar than CCl4. This is because NH3 has a higher electronegativity difference between nitrogen and hydrogen atoms, leading to a greater dipole moment. In contrast, in CCl4, the symmetry of the tetrahedral molecule cancels out the individual dipole moments of the polar C-Cl bonds, resulting in a nonpolar molecule.
The symbol equation for chlorine and carbon combined is: Cl2 + C -> CCl4.
>CCL4 is a non polar molecule. It has 4 polar C-CL bonds due to CL having a higher electronegativity than C (from order of E.N) > The central C atom has 4 regions of negative charge around it. These repel into a tetrahedral arrangement therefore bonding angle: 109.5 degrees, all regions are bonding. therefore the shape is tetrahedral. > The tetrahedral arrangement of polar C-CL bond is symmetrical, therefore polar bonds cancel out as there is no overall/net dipole) therefore CCL4 is a non polar molecule. Hope it helps this is a excellence ncea level 2 answer.