>CCL4 is a non polar molecule.
It has 4 polar C-CL bonds due to CL having a higher electronegativity than C (from order of E.N)
> The central C atom has 4 regions of negative charge around it. These repel into a tetrahedral arrangement therefore bonding angle: 109.5 degrees, all regions are bonding. therefore the shape is tetrahedral.
> The tetrahedral arrangement of polar C-CL bond is symmetrical, therefore polar bonds cancel out as there is no overall/net dipole) therefore CCL4 is a non polar molecule.
Hope it helps this is a excellence ncea level 2 answer.
1 mole CCl4 = 153.811g CCl4 = 6.022 x 1023 molecules CCl4 567g CCl4 x (6.022 x 1023 molecules CCl4)/153.811g CCl4 = 2.22 x 1024 molecules CCl4
This chemical reaction is:CS2 + 3 Cl2 = CCl4 + S2Cl2
2,74 moles of CCL4 is equivalent to 421,44 g.
it will not dissolve NH3 in poler molecules
21.7 g CCl4 (1 mole CCl4/153.81 g)(6.022 X 1023/1 mole CCl4) = 8.50 X 1022 atoms of carbon tetrachloride ===========================
1 mole CCl4 = 153.811g CCl4 = 6.022 x 1023 molecules CCl4 567g CCl4 x (6.022 x 1023 molecules CCl4)/153.811g CCl4 = 2.22 x 1024 molecules CCl4
CCl4 is tetrahedral in shape.
When two liquids are mixed, the term is miscible, not soluble. But yes, CCl4 is miscible in cyclohexane.
CCl4 is also known as carbon tetrachloride. CCl4 is not a unit, but a molecular formula naming its constituent elements and their atomic quantities.
Carbon tetrachloride.
The number of chlorine atoms in 2,00 moles of CCl4 is 48,113.10e23.
The chemical name of CCl4 is carbon tetrachloride.
The balanced equation for the reaction is: CH4 + 4Cl2 -> CCl4 + 4HCl. 1 mole of CH4 produces 1 mole of CCl4. Calculate moles of CH4: 5.14 g / 16.04 g/mol = 0.32 mol. 0.32 mol of CH4 will produce 0.32 mol of CCl4, which is 0.32 * 153.82 g/mol = 49.18 g of CCl4.
This chemical reaction is:CS2 + 3 Cl2 = CCl4 + S2Cl2
Yes it is.
Iodine dissolves readily in CCl4 due to the presence of London dispersion forces between the iodine molecules and the non-polar CCl4 molecules. These weak intermolecular forces allow for iodine molecules to be dispersed throughout the CCl4 solvent.
The reaction CCl4 + 2Cl2 → C + 2CCl2 is a redox reaction, specifically a displacement reaction where CCl4 is being reduced to C and Cl2 is being oxidized to CCl2.