wut the heck is otctene?????????
You need to know how much 1-octene you are starting with. In my lab it was 120 microliters. Change it to liters by dividing by 1000 to make milliliters (mL). I then multiplied by .72 (the density; g/cm3), divided by 112.22 (molecular weight; g/mol). (0.120 mL Octene) x (.72g/cm3) x (1 cm3/1 mL)x (1 mol /112.22 g) x (1 mole H2/1 mole octene). . :)
Bromine in CCl4 is instantly decolorized by 1-octene, because it adds to the double bond, giving 1,2-dibromooctane. Toluene does not give this test because it is aromatic and thus does not add halogens.
Refer to functional groups. Anything with the suffix -ol will be an alcohol, a OH. Anything ending with the suffix -ene will have an alkene, a C-C double bond. Therefore 1-octanol has an alcohol and 1-octene has a C-C double bond.
CH3CH2C(CH3)C(CH2CH2CH3)CH2CH2CH2CH3 24 hydrogen
cis CH3-CH=CHCl trans CH3-CH=CHCl CH3-CCl=CH2 CH2Cl-CH=CH2 Chlorocyclopropane - a cyclopropane with a chlorine attached source http://chemistrysat.blogspot.com/2007/03/sat-question-of-day.html
No, 2-octene is not soluble in water because it is a nonpolar compound and water is a polar solvent. Nonpolar compounds like 2-octene are not able to form favorable interactions with water molecules, leading to poor solubility.
You need to know how much 1-octene you are starting with. In my lab it was 120 microliters. Change it to liters by dividing by 1000 to make milliliters (mL). I then multiplied by .72 (the density; g/cm3), divided by 112.22 (molecular weight; g/mol). (0.120 mL Octene) x (.72g/cm3) x (1 cm3/1 mL)x (1 mol /112.22 g) x (1 mole H2/1 mole octene). . :)
The equation for the reaction of 1-octene with sulfuric acid is as follows: H2CCHCH2CH2CH2CH2CH2CH3 + H2SO4 ----> CH3CCHOSO2OHCH2CH2CH2CH2CH2CH3. This is otherwise known as octyl hydrogensulphate. The major product is markovnikov.
The boiling point of 1-hexene is 63 0C.The boiling point of 1-octene is 121 0C.
N-octyl alcohol and 1-octene would be most easily separated by thin layer chromatography due to their differences in polarity. Hexadecane and octadecane, being nonpolar hydrocarbons, may be more challenging to separate as their chemical properties are more similar.
1-octanol is an alcohol, so it has an OH group attached to the first C atom. (C8H17OH) 1-octene is an alkene, which has a double bond between the first and second C atoms. (C8H16)
Yes, 3-octene can exhibit cis-trans isomerism. In the cis isomer, the two methyl groups are on the same side of the double bond, while in the trans isomer, they are on opposite sides.
Bromine in CCl4 is instantly decolorized by 1-octene, because it adds to the double bond, giving 1,2-dibromooctane. Toluene does not give this test because it is aromatic and thus does not add halogens.
The structural formula for cis-4-octene is CH3(CH2)6CH=CHCH3. It consists of an eight-carbon chain with a double bond between the fourth and fifth carbons, and the two methyl groups are on the same side of the double bond, giving it the cis configuration.
Refer to functional groups. Anything with the suffix -ol will be an alcohol, a OH. Anything ending with the suffix -ene will have an alkene, a C-C double bond. Therefore 1-octanol has an alcohol and 1-octene has a C-C double bond.
CH3CH2C(CH3)C(CH2CH2CH3)CH2CH2CH2CH3 24 hydrogen
This is a catalyst. You need one drop for this lab. One drop is 50mcL.