Vinegar
The balanced chemical equation for the reaction is H2SO4 + 2NaOH -> Na2SO4 + 2H2O. From the mole ratio, 1 mole of H2SO4 reacts with 2 moles of NaOH. Using the volume and concentration of NaOH, we can calculate the moles of NaOH used. Then, knowing the moles of NaOH used and the volume of H2SO4, we can find the concentration of sulfuric acid.
Perhaps the acid H2SO4 ( sulfuric acid ) and the base NaOH ( sodium hydroxide )
Grams NaOH?? Balanced equation. 2NaOH + H2SO4 --> Na2SO4 + 2H2O 4.9 grams H2SO4 (1 mole H2SO4/98.086 grams)(2 mole NaOH/1 mole H2SO4)(39.998 grams/1 mole NaOH) = 4.0 grams NaOH needed =================
When sulfuric acid (H2SO4) reacts with sodium hydroxide (NaOH), the salt produced is sodium sulfate (Na2SO4) along with water.
For every mole of sodium hydroxide, you need 1 mole of sulfuric acid for neutralization. The molar mass of sodium hydroxide (NaOH) is 40.0 g/mol and sulfuric acid (H2SO4) is 98.1 g/mol. So, to neutralize 40 g of NaOH (1 mole), you would need 98.1 g of H2SO4 (1 mole). Therefore, to neutralize 10.0 g of NaOH, you would need 24.53 g of H2SO4.
The balanced chemical equation for the reaction is H2SO4 + 2NaOH -> Na2SO4 + 2H2O. From the mole ratio, 1 mole of H2SO4 reacts with 2 moles of NaOH. Using the volume and concentration of NaOH, we can calculate the moles of NaOH used. Then, knowing the moles of NaOH used and the volume of H2SO4, we can find the concentration of sulfuric acid.
Perhaps the acid H2SO4 ( sulfuric acid ) and the base NaOH ( sodium hydroxide )
Grams NaOH?? Balanced equation. 2NaOH + H2SO4 --> Na2SO4 + 2H2O 4.9 grams H2SO4 (1 mole H2SO4/98.086 grams)(2 mole NaOH/1 mole H2SO4)(39.998 grams/1 mole NaOH) = 4.0 grams NaOH needed =================
When sulfuric acid (H2SO4) reacts with sodium hydroxide (NaOH), the salt produced is sodium sulfate (Na2SO4) along with water.
For every mole of sodium hydroxide, you need 1 mole of sulfuric acid for neutralization. The molar mass of sodium hydroxide (NaOH) is 40.0 g/mol and sulfuric acid (H2SO4) is 98.1 g/mol. So, to neutralize 40 g of NaOH (1 mole), you would need 98.1 g of H2SO4 (1 mole). Therefore, to neutralize 10.0 g of NaOH, you would need 24.53 g of H2SO4.
Perchloric acid (HClO4) is a stronger acid than sulfuric acid (H2SO4) because perchloric acid has a more acidic hydrogen that is easier to release as a proton, resulting in a stronger acid.
No, carbonic acid is stronger than vinegar. Carbonic acid is formed when carbon dioxide dissolves in water, whereas vinegar is a weaker acid composed of acetic acid.
Sulfuric acid plus sodium hydroxide gives sodium sulfate plus water.
sulfuric acid + sodium hydroxide ---> sodium sulfate + water
Since H2SO4 is a diprotic acid, it will require twice the amount of NaOH to neutralize it. Therefore, molarity of NaOH should also be 1 M. 1 mole of H2SO4 reacts with 2 moles of NaOH. Therefore, to neutralize 1 mole of H2SO4, 2 moles of NaOH are required. To neutralize 1 mole of H2SO4 in 100 ml (0.1 L) of 1 M solution, you will need 0.1 moles of NaOH.
The reaction is the following: H2SO4 + 2NaOH = Na2SO4 + 2H2O
baking soda is a base while vinegar is an acid