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What is the balanced chemical equation for the combustion of C12H26?
The balanced equation would be; C25H52(s) + 38 O2(g) -> 25 CO2(g) + 26 H2O(l)
If you start with 45 grams of ethylene how many grams of carbon dioxide will be produced?
If ethylene (C2H4) undergoes complete combustion, it will react with oxygen to produce carbon dioxide and water. The balanced chemical equation for the combustion of ethylene is: C2H4 + 3 O2 → 2 CO2 + 2 H2O. Since 1 mol of C2H4 produces 2 mol of CO2, the molar ratio is 1:2. Therefore, starting with 45 grams of ethylene, it will result in 120 grams of carbon dioxide being produced.
Which has more molecules a gram of CO2 or a gram of H2?
A gram of CO2 has more molecules than a gram of H2 because CO2 has more atoms per molecule (three atoms in CO2 compared to two in H2). Thus, CO2 will have a higher total number of molecules per gram.
Is NO2 more acidic than CO2?
Yes, NO2 is more acidic than CO2.
What is the chemical eqaution of oxidation for ethane?
2 C2H6 + 7 O2 → 4 CO2 + 6 H2O + 3170 kJ of exothermic energy.
Write the balanced equation for the combustion in air of Dodecane?
c12h26(i)--->c2h4(g)+______ Yuu shud work iht ouwt :)
How the equation C2H4 02 - CO2 H2O balance?
C2h4 + o2 ------------- co2 + h2o c2h4 + 3o2 ------------- 2co2 + 2h2o
When 125 grams of C2H4 burns in oxygen to give carbon dioxide and water how many grams of CO2 are formed?
Balanced equation C2H4 + 3O2 -> 2CO2 + 2H2O 125 grams ethylene (1 mole C2H4/28.052 grams)(2 mole CO2/1 mole C2H4)(44.01 grams/1 moleCO2) = 392 grams CO2 formed ==================
What is the balanced chemical equation for the combustion of C12H26?
The balanced equation would be; C25H52(s) + 38 O2(g) -> 25 CO2(g) + 26 H2O(l)
What mass of CO2 is produced when 50.0 g of C2 H4 reacts completely in C2 H4 plus 3 O2 equals 2 CO2 plus 2 H20?
To find the mass of CO2 produced, first calculate the moles of C2H4 using its molar mass. Then, use the balanced equation to determine the moles of CO2 produced per mole of C2H4 reacted. Finally, convert moles of CO2 to grams using the molar mass of CO2.
What numbers would properly balance the reaction c12h26 plus o2-co2 plus H2O?
2c12h26 +37o2 = 24co2 + 26h2o
Use the following balanced chemical equation to calculate the mass of carbon dioxide produced from the burning of 3.73 kg of jet fuel which can be represented by the molecule C12H26 You?
First, calculate the molar mass of C12H26 (dodecane) by multiplying the molar masses of carbon and hydrogen and summing them up. Then determine the moles of C12H26 in 3.73 kg by dividing the mass by the molar mass. As the balanced equation shows a 1:12 ratio between C12H26 and CO2, multiply the moles of C12H26 by 12 to find the moles of CO2 produced. Finally, determine the mass of CO2 by multiplying the moles by its molar mass.
Why C2H4 plus 3 O2 2 CO2 plus 2 H2O H -1410 kJ?
The reaction C2H4 + 3 O2 → 2 CO2 + 2 H2O is an example of the combustion of ethylene (C2H4), where the hydrocarbon reacts with oxygen to produce carbon dioxide and water. The ΔH of -1410 kJ indicates that this reaction is exothermic, meaning it releases energy in the form of heat. This energy release occurs due to the formation of strong bonds in the products (CO2 and H2O) that release more energy than is required to break the bonds in the reactants (C2H4 and O2). Thus, the negative enthalpy change signifies a net loss of energy to the surroundings during the reaction.
What would be the final value for the enthalpy of reaction you use for this intermediate reaction C2H4 plus 3 O2 2 CO2 plus 2 H2O H -1410 kJ?
The final value for the enthalpy of reaction for the combustion of ethylene (C2H4) in your given reaction is -1410 kJ. This indicates that the reaction is exothermic, releasing 1410 kJ of energy as products (2 CO2 and 2 H2O) are formed from the reactants (C2H4 and 3 O2). Therefore, the enthalpy change, ΔH, for the complete combustion of ethylene is -1410 kJ.
If you start with 45 grams of ethylene how many grams of carbon dioxide will be produced?
If ethylene (C2H4) undergoes complete combustion, it will react with oxygen to produce carbon dioxide and water. The balanced chemical equation for the combustion of ethylene is: C2H4 + 3 O2 → 2 CO2 + 2 H2O. Since 1 mol of C2H4 produces 2 mol of CO2, the molar ratio is 1:2. Therefore, starting with 45 grams of ethylene, it will result in 120 grams of carbon dioxide being produced.
How many molecules of water can be produced by the reaction of 2.16 mol of oxygen with excess Ethylene.?
C2H4 + 3 O2 --> 2 CO2 + 2 H2OSo 2.16 mol O2 will produce 1.44 mol H2O(and 1.44 mol CO2)because 3:2 = 2.16 : 1.44
What volume of oxygen at stpis neededto react with 1.50 moles of c2h4?
To answer this question, it is necessary to have an equation for the reaction. The most common such reaction is complete combustion, which follows the equation: C2H4 + 3 O2 = 2 CO2 + 2 H2O. This equation shows that 3 moles of diatomic oxygen are required to react completely with one mole of C2H4. Therefore, for 1.50 moles of C2H4, 3 X 1.5 = 4.50 moles of oxygen will be required. Oxygen is close to an ideal gas at standard temperature and pressure. Each mole of ideal gas at stp occupies 22.4 liters. Therefore, 4.50 X 22.4 = 101 liters of oxygen, to the justified number of significant digits, will be needed.
