4Fe(s) + 3O2(g) --> 2Fe2O3(s)
The reactions are:4 Fe + 3 O2 + 2 H2O = 4 FeO(OH)2 FeO(OH) -------Fe2O3 + H2O
The balanced equation is 2Fe2O3 + 4Al ----> 2Al2O3 + 3Fe. The coefficient of Fe is 3.
The chemical equation for the hydration of Fe2O3 to form rust is: Fe2O3 + 3H2O → 2Fe(OH)3. In this reaction, iron(III) oxide (Fe2O3) reacts with water to form iron(III) hydroxide (Fe(OH)3), which is known as rust.
If the moles of Fe2O3 are known, you would use the mole ratio from the balanced chemical equation for the reaction involving Fe2O3 and Fe. In the balanced equation, the mole ratio between Fe2O3 and Fe is 2:2, which simplifies to 1:1. This means that for every mole of Fe2O3, there is an equivalent mole of Fe.
The chemical formula for iron(III) oxide is Fe2O3. This indicates that each iron atom is bonded to three oxygen atoms in the compound.
To balance the chemical equation for the reaction of Al and Fe2O3 to produce Al2O3 and Fe, you need to ensure that the number of atoms for each element is the same on both sides of the equation. First, write the unbalanced equation: Al + Fe2O3 -> Al2O3 + Fe. Then, adjust the coefficients of each compound until the number of atoms of each element balances out. Solution: 2Al + Fe2O3 -> Al2O3 + 2Fe.
The reactions are:4 Fe + 3 O2 + 2 H2O = 4 FeO(OH)2 FeO(OH) -------Fe2O3 + H2O
The balanced equation is 2Fe2O3 + 4Al ----> 2Al2O3 + 3Fe. The coefficient of Fe is 3.
The chemical equation for the hydration of Fe2O3 to form rust is: Fe2O3 + 3H2O → 2Fe(OH)3. In this reaction, iron(III) oxide (Fe2O3) reacts with water to form iron(III) hydroxide (Fe(OH)3), which is known as rust.
The chemical equation is:4 Fe + 3 O2 = 2 Fe2O3
The chemical equation is:2 Fe + 3 Ag2O = 6Ag + Fe2O3
3Fe + 4(H2O) ---> Fe3O4 + 4(H2) You really should learn this, its not that hard =D
If the moles of Fe2O3 are known, you would use the mole ratio from the balanced chemical equation for the reaction involving Fe2O3 and Fe. In the balanced equation, the mole ratio between Fe2O3 and Fe is 2:2, which simplifies to 1:1. This means that for every mole of Fe2O3, there is an equivalent mole of Fe.
The balanced chemical equation for the formation of iron(III) oxide (Fe2O3) from iron (Fe) and oxygen (O2) is: 4 Fe + 3 O2 → 2 Fe2O3. From the equation, it can be seen that 3 moles of O2 are required to produce 2 moles of Fe2O3. Therefore, to produce 107.9 moles of Fe2O3, you would need (107.9 moles Fe2O3) × (3 moles O2 / 2 moles Fe2O3) = 161.85 moles of O2.
The chemical formula for iron(III) oxide is Fe2O3. This indicates that each iron atom is bonded to three oxygen atoms in the compound.
In the balanced chemical equation 4Fe + 3O2 -> 2Fe2O3, the coefficient in front of iron (Fe) is 4.
Fe2O3 + C --> Fe + CO2 balances it's 2 iron oxides, three carbons, 4 irons and 3 CO2s :)