What is listed are all examples of just onemolecule. O2 is one molecule of oxygen, CO2 is one molecule of carbon dioxide, and NH3 is one molecule of ammonia. Perhaps you're asking which has the largest number of atoms? In that case, the answer is ammonia, with a total of four atoms.
The pair of molecules with the strongest dipole-dipole interactions would be NH3-NH3 because ammonia (NH3) is a polar molecule with a significant dipole moment, leading to stronger attractions compared to the other options listed.
To find the number of molecules in 0.95 grams of SF6, you would first calculate the number of moles of SF6 using its molar mass. Then, using Avogadro's number, you can determine the number of molecules. Next, you would convert this number of molecules to the number of moles of NH3 using the mole ratio between NH3 and SF6. Finally, you would convert the moles of NH3 to grams using the molar mass of NH3 to find the mass needed.
7.95 X 1022 molecules NH3 (1 mole NH3/6.022 X 1023) = 0.132 moles ammonia =================
To find the mass of 1.75 x 10^24 molecules of NH3, you would first calculate the molar mass of NH3 (17.03 g/mol). Then, you would convert the number of molecules to moles by dividing by Avogadro's number (6.022 x 10^23 molecules/mol). Finally, multiply the number of moles by the molar mass to find the mass.
The number of molecules is 0,391439155705.10e23.
The pair of molecules with the strongest dipole-dipole interactions would be NH3-NH3 because ammonia (NH3) is a polar molecule with a significant dipole moment, leading to stronger attractions compared to the other options listed.
To find the number of molecules in 0.95 grams of SF6, you would first calculate the number of moles of SF6 using its molar mass. Then, using Avogadro's number, you can determine the number of molecules. Next, you would convert this number of molecules to the number of moles of NH3 using the mole ratio between NH3 and SF6. Finally, you would convert the moles of NH3 to grams using the molar mass of NH3 to find the mass needed.
7.95 X 1022 molecules NH3 (1 mole NH3/6.022 X 1023) = 0.132 moles ammonia =================
To find the mass of 1.75 x 10^24 molecules of NH3, you would first calculate the molar mass of NH3 (17.03 g/mol). Then, you would convert the number of molecules to moles by dividing by Avogadro's number (6.022 x 10^23 molecules/mol). Finally, multiply the number of moles by the molar mass to find the mass.
The number of molecules is 0,391439155705.10e23.
CO2 and SF4 exhibit resonance because they both have multiple resonance structures due to the presence of multiple double bonds. BH3 and NH3 do not exhibit resonance as they are both stable molecules with no additional resonance structures.
To find the number of molecules produced, first calculate the number of moles of H2 using its molar mass. Then, use the balanced chemical equation to relate the number of moles of H2 to NH3. Finally, convert the moles of NH3 to molecules using Avogadro's number, which is 6.022 x 10^23 molecules/mol.
NH3 Molecules = ( 8.1 x 10^20 H atoms ) ( 1 NH3 molecule / 3 H atoms ) NH3 Molecules = 2.7 x 10^20 NH3 molecules NH3 moles = ( NH3 molecules ) / ( N Avogadro ) NH3 moles = ( 2.7 x 10^20 NH3 molecules ) / ( 6.022 x 10^23 molecules / mole ) NH3 moles = 4.48 x 10^-4 NH3 moles <--------------
BCl3 and NH3 would exhibit dipole-dipole intermolecular forces, as they have polar bonds. CF4, CO2, and Cl2 would not exhibit dipole-dipole forces, as they are nonpolar molecules.
To find the mass in grams of 1.20x10^25 molecules of ammonia (NH3), you first calculate the molar mass of NH3 (17.031 g/mol). Then, divide the given number of molecules by Avogadro's number (6.022x10^23 molecules/mol) to find the number of moles, and finally, multiply the number of moles by the molar mass to get the mass in grams, which will be approximately 4.08x10^2 grams.
molar mass NH3 = 17 g/molmolar mass SF6 = 146 g/molmolecules in 0.55g SF6 = 0.55g x 1mol/146g x 6.02x10^23 molecules/mole = 2.27x10^21 moleculesgrams NH3 needed = 2.27x10^21 molecules x 1mol/6.02x10^23 molecules x 17g/mol = 0.064 grams
To find the number of ammonia molecules in 3.75g of CH4, you first need to convert 3.75g of CH4 to moles using the molar mass. Then, you need to use the mole ratio between CH4 and NH3 to find the number of ammonia molecules in the given amount of CH4. The mole ratio for CH4 to NH3 is 1:3, as 1 molecule of CH4 produces 3 molecules of NH3 in the balanced chemical equation.