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Dissolving and hydratation reaction (this gives the blue color of Cu hydrated ions)

CuSO4 + 4H2O --> Cu(H2O)42+ + SO42-

followed by two differend protolysis reactions, of which the first is relatively stronger acidic than the second (wich is very weakly basic):

  1. Cu(H2O)42+ + H2O ==> Cu(OH)(H2O)3+ + H3O+
  2. SO42- + H2O --> HSO4- + OH-
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