There are reasons.
First, it takes more energy more energy and therefore costs to extract the needed sodium from its compounds than it is to simply get the hydrogen by electrolysis of water.
Second, the reaction between sodium and any acid is violent, even explosive, making it dangerous to conduct even on a small scale.
Third, the heat produced by the reaction is enough to ignite the hydrogen, which would then form only common water.
The dissociation is:NaHCO3-------------Na+ + (HCO3)-
First you need to find the theoretical yield for the reaction:2Na + O2 ---> Na2O2(1) find the theoretical yield of 3.74 g of Na, i.e. if all of the Na is reacted3.74 g Na *(1 mol Na/22.99 g Na)*(1 mol Na2O2 formed/2 mol Na reacted)*(77.98 g Na2O2/1 mol Na2O2) = 6.34 g Na2O2(2) % yield = (actual yield / theoretical yield)*(100%)% yield = (5.34 g / 6.34 g) *(100%) = 84.2% yield
Using the equation 2Na + 2HCl -> 2NaCl + H2, we can see that 2 moles of Na react with 2 moles of HCl to produce 1 mole of H2. Calculate moles of Na: 25g Na * 1 mol Na / 23g Na = 1.09 mol Na. Since the reaction is with excess HCl, the number of moles of H2 produced will be half the number of moles of Na, so it will be 0.545 moles of H2.
The reactants are sodium metal (Na) and hydrochloric acid (HCl). The chemical reaction between them produces salt (NaCl) and hydrogen gas (H2).
Na+ + OH- + H+ + Cl- H2O + Na+ + Cl-
The dissociation is:NaHCO3-------------Na+ + (HCO3)-
The reactants in this reaction are sodium (Na) and hydrochloric acid (HCl).
First you need to find the theoretical yield for the reaction:2Na + O2 ---> Na2O2(1) find the theoretical yield of 3.74 g of Na, i.e. if all of the Na is reacted3.74 g Na *(1 mol Na/22.99 g Na)*(1 mol Na2O2 formed/2 mol Na reacted)*(77.98 g Na2O2/1 mol Na2O2) = 6.34 g Na2O2(2) % yield = (actual yield / theoretical yield)*(100%)% yield = (5.34 g / 6.34 g) *(100%) = 84.2% yield
no metal can not react with acid to give Carbondioxide gas but a hydrogen gas HCl + Na-------->NaCl(s) + H(g)
The balanced chemical equation for the reaction between sodium and water is: 2Na + 2H2O -> 2NaOH + H2 This means that for every mole of sodium (Na) reacted, one mole of hydrogen gas (H2) is produced. Therefore, when 0.066 mole of sodium is reacted, 0.066 mole of hydrogen gas will be produced.
Yes. Example: 2 Na + 2 HCl ---> 2 NaCl + H2 Sodium (Na) is a metal.HCl is hydrochloric acid. Sodium Chloride (NaCl) is a salt.
Using the equation 2Na + 2HCl -> 2NaCl + H2, we can see that 2 moles of Na react with 2 moles of HCl to produce 1 mole of H2. Calculate moles of Na: 25g Na * 1 mol Na / 23g Na = 1.09 mol Na. Since the reaction is with excess HCl, the number of moles of H2 produced will be half the number of moles of Na, so it will be 0.545 moles of H2.
The reactants in this reaction are sodium (Na) and hydrochloric acid (HCl).
Na2So4
Sodium chloride contain sodium and chlorine; hydrogen chloride contain chlorine and hydrogen. They are dissociated in water solutions: HCl----------H+ + Cl- NaCl---------Na+ + Cl-
The reactants are sodium metal (Na) and hydrochloric acid (HCl). The chemical reaction between them produces salt (NaCl) and hydrogen gas (H2).
There is no such thing as Sodium Hydrochloric acid, but if you react Sodium metal with Hydrochloric acid, you will release hydrogen. The hydrogen comes from hydrochloric acid, which is HCl (hydrogen chloride.) Sodium is Na, just a pure element without any hydrogen in it. 2Na + 2HCl --> 2NaCl + H2 (gas) You don't need HCl to make hydrogen gas. Just tossing the sodium into water will release plenty of hydrogen (and some flames) and give a solution of sodium hydroxide in the water.