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In ammonia the N atom because it is period 2 can only realistically hybridize as sp, sp2 or sp3. The geometry is trigonal pyramidal, so sp3 hybridisation is the best fit, the other options would not fit the geometry.

In actuality the bond angle of 1070 shows that as the angle is closer to 90 than in "true" sp3 (1090)the bonds have slightly more p character (porbitals are at 900), leaving the lone pair with slightly more s character..

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12y ago

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