Both have no lone pairs.They have even bonds
In SiH4 (silane), the dominant intermolecular force is London dispersion forces (van der Waals forces) due to the temporary dipoles created by the movement of electrons around the silicon-hydrogen bonds. There are no permanent dipoles in SiH4, so dipole-dipole interactions are negligible.
first you set up your ratio; 9.3moles 1mole = 32g 9.3 is the number of moles you're trying to find 32 comes from adding the mass numbers of both elements; Si=28g H=1g, but there's four, so you multiply it by 4, hence the 32 now you crossmultiply; so multiply 9.3 by 32 you get 297.6, then divide by 1 so 9.3 moles SiH4 is 297.6g. follow the same pattern every time and you'll be fine; hope this helps
Carbon has a atomic mass of 12.So its percentage is 75%
200 g CH4 x 1 mole CH4/16 g = 12.5 moles CH4
no
In SiH4 (silane), the dominant intermolecular force is London dispersion forces (van der Waals forces) due to the temporary dipoles created by the movement of electrons around the silicon-hydrogen bonds. There are no permanent dipoles in SiH4, so dipole-dipole interactions are negligible.
first you set up your ratio; 9.3moles 1mole = 32g 9.3 is the number of moles you're trying to find 32 comes from adding the mass numbers of both elements; Si=28g H=1g, but there's four, so you multiply it by 4, hence the 32 now you crossmultiply; so multiply 9.3 by 32 you get 297.6, then divide by 1 so 9.3 moles SiH4 is 297.6g. follow the same pattern every time and you'll be fine; hope this helps
because ch4 has an octett and bh3 not so it dimerises to b2h6
CH4 --> CO2 is a 1 to 1 reaction (C-balanced) when burning with oxygen. So 1 mole CH4 --> 1 mole CO2 So 1 Litere CH4 --> 1 Liter CO2 So 16 grams CH4 --> 44 grams CO2
Because their bodies are like humans. They have similar structures to us, so if they can survive, so can we.
No it does not. All sides have a Hydrogen so no matter where you move it to, its still the same Lewis structure.
To determine the limiting reagent, we need to compare the amount of each reactant to their stoichiometric coefficients in the balanced equation. The balanced equation for the combustion of CH4 with O2 is: CH4 + 2O2 -> CO2 + 2H2O. From the given amounts, we can see that O2 is in excess, so CH4 is the limiting reagent.
Carbon has a atomic mass of 12.So its percentage is 75%
The balanced chemical equation for the reaction is: CH4 + 2O2 -> CO2 + 2H2O Using the molar masses of CH4 and O2, we can calculate the moles present in 24g of CH4 and 96g of O2. From there, we can determine the limiting reactant and the amount of product formed.
It is either homologous structures or homozygous structures. Embryological structures are when different species of animals look similar in the earliest stage of development and Analogous structures are when animals look different but their function is basically the same. So just look up homologous structures and homozygous structures in your Bio book!!
200 g CH4 x 1 mole CH4/16 g = 12.5 moles CH4
Methane is a gas and so takes the shape of the container that it is in.