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Acetoacetic ester can react like a ketone because it contains a carbonyl group that can participate in typical ketone reactions such as nucleophilic addition. It can also react like an alkene because the enol form of acetoacetic ester can undergo tautomerization to form a more stable carbonyl compound, allowing it to participate in alkene-like reactions such as electrophilic addition.

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Why does alkene reacts kmno4?

Alkenes react with potassium permanganate (KMnO4) through a process called oxidative cleavage, where the double bond is broken and oxygen atoms are added to the carbon atoms. This reaction results in the formation of diols (glycols) or ketones and carboxylic acids, depending on the conditions and the structure of the alkene.


How does potassium permanganate (KMnO4) react with alkenes?

Potassium permanganate (KMnO4) reacts with alkenes through a process called oxidative cleavage. This reaction breaks the double bond in the alkene, resulting in the formation of diols or ketones, depending on the specific conditions of the reaction.


Why is it not possible to selectively epoxidize an alkene with mCPBA in the presence of a ketone?

It is not possible to selectively epoxidize an alkene with mCPBA in the presence of a ketone because mCPBA can react with both the alkene and the ketone, leading to non-selective reactions and the formation of undesired byproducts.


Why Tollens reagent does not react with ketone?

Tollens reagent is a mild oxidizing agent that reacts with aldehydes to produce a silver mirror. Ketones, however, do not have a hydrogen atom bonded to the carbonyl group, making them resistant to oxidation by Tollens reagent. As a result, ketones do not react with Tollens reagent.


What is the reagent to distinguish alkene and alkyne?

Bromine in water or bromine water can be used to distinguish between an alkene and an alkyne. Alkenes will decolorize bromine water by undergoing addition reactions, while alkynes will not react under normal conditions and will not decolorize bromine water.

Related Questions

How does ketones react with sodium bicarbonate?

Ketones or Aldehydes DO NOT react with Sodium Bicarbonate..generally only Carboxilic acids have the ability to do it!


Why does alkene reacts kmno4?

Alkenes react with potassium permanganate (KMnO4) through a process called oxidative cleavage, where the double bond is broken and oxygen atoms are added to the carbon atoms. This reaction results in the formation of diols (glycols) or ketones and carboxylic acids, depending on the conditions and the structure of the alkene.


How does potassium permanganate (KMnO4) react with alkenes?

Potassium permanganate (KMnO4) reacts with alkenes through a process called oxidative cleavage. This reaction breaks the double bond in the alkene, resulting in the formation of diols or ketones, depending on the specific conditions of the reaction.


Why KCN fail to react with aldehyde and ketones?

KCN does not react with aldehydes and ketones because these compounds do not have an acidic hydrogen that can be removed to form an enolate ion, which is necessary for nucleophilic addition reactions with cyanide ions. Aldehydes and ketones lack the necessary alpha carbon acidity to undergo this reaction with KCN.


Why is it not possible to selectively epoxidize an alkene with mCPBA in the presence of a ketone?

It is not possible to selectively epoxidize an alkene with mCPBA in the presence of a ketone because mCPBA can react with both the alkene and the ketone, leading to non-selective reactions and the formation of undesired byproducts.


Why Tollens reagent does not react with ketone?

Tollens reagent is a mild oxidizing agent that reacts with aldehydes to produce a silver mirror. Ketones, however, do not have a hydrogen atom bonded to the carbonyl group, making them resistant to oxidation by Tollens reagent. As a result, ketones do not react with Tollens reagent.


When preforming the bromine test to distinguish between aromatic and alkene compound?

In the bromine test, an alkene compound will decolorize a bromine solution whereas an aromatic compound will not react with the bromine solution. This is because the double bond in the alkene readily reacts with bromine to form a colorless product, while the stable aromatic ring in the aromatic compound does not undergo such reaction.


What is the reagent to distinguish alkene and alkyne?

Bromine in water or bromine water can be used to distinguish between an alkene and an alkyne. Alkenes will decolorize bromine water by undergoing addition reactions, while alkynes will not react under normal conditions and will not decolorize bromine water.


What happened with Hexane and hexene when it is combined with HCL and also NaOH?

There will be no reaction of Hexane as it does'nt have any reactive sites. Hexene will react only with Hcl as the double bond is nucleophilic to give poly chlorinated hexane. Hexene will not react with NaOH


What is the mechanism of the Tollens test and how does it differentiate between aldehydes and ketones?

The Tollens test involves the oxidation of aldehydes to carboxylic acids by silver ions in a basic solution. This forms a silver mirror on the inside of the test tube. Ketones do not react with Tollens reagent and do not produce a silver mirror. This test is used to differentiate between aldehydes and ketones based on their reactivity with Tollens reagent.


Why ketone do not react with Fehlings solution and Tollens reagent?

Ketones do not react with Fehling's solution or Tollens' reagent because they lack the free aldehyde group necessary for these reactions to occur. Both Fehling's solution and Tollens' reagent depend on the presence of the aldehyde group to participate in redox reactions that lead to the formation of a colored precipitate. Without this aldehyde group, ketones do not undergo these reactions.


What is the reaction between alcoholic KOH and alkyl halide?

Alcoholic KOH (potassium hydroxide in alcohol) reacts with an alkyl halide through an elimination reaction called the E2 mechanism to form an alkene. The alkyl halide undergoes deprotonation by the strong base (KOH) and elimination of the halogen atom to generate the alkene product.