Alpha hydrogens are removed in aldol condensation to form enolate ions, which are more reactive nucleophiles than the carbonyl group itself. This leads to faster and more efficient formation of the carbon-carbon bond between two carbonyl compounds. Removing the alpha hydrogens also helps stabilize the enolate ion through resonance, making the reaction more favorable.
Only those aldehydes may undergo the aldol condensation which have the alpha hydrogen (hydrogen at carbon adjacent to carbonyl carbon) in benzaldehyde alpha carbon is not present so it can not undergoes the aldol condensation.
Compounds which have CH3CO- group or compounds that can be converted to CH3CO- group undergo aldol condensation. 1-propanol doesn't undergo aldol condensation. However 2-propanol undergoes aldol condensation.
Aldol condensation is the reaction of two aldehydes in the presence of a basic catalyst. The aldol condensation leads to an aldol product, in which an hydroxyl group is attached to the beta carbon of an aldehyde. Claisen condensation is similar to aldol condensation, but is involves two esters instead of two aldehydes. The product of a Claisen condensation is a beta-keto-ester, a compound characterized by an ester with its alpha carbon being a ketone.
Yes, 2-hydroxy-2-methyl pentanal can be formed as a product of aldol condensation. Aldol condensation typically involves the reaction between an aldehyde or ketone with an enolate ion, leading to the formation of a beta-hydroxy aldehyde or ketone. In this case, the given compound fits the description of a beta-hydroxy aldehyde, which can be a product of aldol condensation.
All condensation reactions proceed with formation of water (H2O). If you look at the reaction mechanism for Aldol condensation, you will observe that water is formed as an end-product of the reaction.
Only those aldehydes may undergo the aldol condensation which have the alpha hydrogen (hydrogen at carbon adjacent to carbonyl carbon) in benzaldehyde alpha carbon is not present so it can not undergoes the aldol condensation.
Compounds which have CH3CO- group or compounds that can be converted to CH3CO- group undergo aldol condensation. 1-propanol doesn't undergo aldol condensation. However 2-propanol undergoes aldol condensation.
Aldol condensation is the reaction of two aldehydes in the presence of a basic catalyst. The aldol condensation leads to an aldol product, in which an hydroxyl group is attached to the beta carbon of an aldehyde. Claisen condensation is similar to aldol condensation, but is involves two esters instead of two aldehydes. The product of a Claisen condensation is a beta-keto-ester, a compound characterized by an ester with its alpha carbon being a ketone.
Aldol condensation is the reaction of two aldehydes in the presence of a basic catalyst. The aldol condensation leads to an aldol product, in which an hydroxyl group is attached to the beta carbon of an aldehyde. Claisen condensation is similar to aldol condensation, but is involves two esters instead of two aldehydes. The product of a Claisen condensation is a beta-keto-ester, a compound characterized by an ester with its alpha carbon being a ketone.
Yes, 2-hydroxy-2-methyl pentanal can be formed as a product of aldol condensation. Aldol condensation typically involves the reaction between an aldehyde or ketone with an enolate ion, leading to the formation of a beta-hydroxy aldehyde or ketone. In this case, the given compound fits the description of a beta-hydroxy aldehyde, which can be a product of aldol condensation.
All condensation reactions proceed with formation of water (H2O). If you look at the reaction mechanism for Aldol condensation, you will observe that water is formed as an end-product of the reaction.
Actually the base eg OH group attacks on the alpha Hydrogen atom thus releasing the carbanion and itself forming water. The carbanion further reacts with another aldehyde molecule forming methoxide ion which reacts with water to form aldol product and releases the OH group.
Not really because aldol condensation of 2 CH3CHO would be a major competing process.
crotonaldhyde CH3-CH=CH-CHO
ethyl acetate undergoes aldol condensation with benzaldehyde. in the aldol product the aceto group undergoes enolisation. Urea attacks through 1,4 addition.
The use of sodium bicarbonate in an aldol condensation reaction helps to neutralize any acidic byproducts that may form during the reaction. This can prevent side reactions and improve the yield of the desired product.
well based on my studies two compounds are produced, viz: ethanedial and methanal