When two aqueous solutions are mixed, a precipitation reaction may occur if the products formed are insoluble in water. Whether a precipitate forms depends on the solubility of the compounds involved. If a solid product is formed, it is called a precipitate.
The net ionic equation for the reaction between Na3PO4(aq) and CaCl2(aq) is: 3 Na+(aq) + 2 PO4^3-(aq) + 3 Ca^2+(aq) + 6 Cl-(aq) → 6 Na+(aq) + 2 Ca3(PO4)2(s) This equation shows the formation of solid calcium phosphate when sodium phosphate and calcium chloride are mixed.
The spectator ion is NO3- from Ba(NO3)2, as it remains unchanged throughout the reaction and does not participate in forming the precipitate of Ba3(PO4)2.
The ionic equation is 2K+(aq) + 2OH-(aq) + Co^2(aq) + 2Br^-(aq) ==> 2K+(aq) + 2Br-(aq) + Co(OH)2(s)net ionic equation is Co2+(aq) + 2OH-(aq) ==> Co(OH)2(s)So spectators are K+ and Br- ions.
Mg(NO3)2(aq) + H2SO4(aq) ==> MgSO4(aq) + 2HNO3(aq) Complete molecular equationTotal ionic equation:Mg^2+(aq) + 2NO3^-(aq) + 2H^+(aq) + SO4^2-(aq) => Mg^2+(aq) + SO4^2-(aq) + 2H^+(aq) + 2NO3^-(aq)RESULT - NO REACTION
The precipitation reaction between potassium hydroxide (KOH) and nickel(II) bromide (NiBr2) can be represented by the following equation: 2 KOH(aq) + NiBr2(aq) → Ni(OH)2(s) + 2 KBr(aq)
When solutions of KCl and Pb(NO3)2 are mixed, lead(II) chloride (PbCl2) precipitates. The molecular equation is: [ \text{2 KCl (aq) + Pb(NO}_3\text{)}_2\text{ (aq) } \rightarrow \text{ 2 KNO}_3\text{ (aq) + PbCl}_2\text{ (s)} ] The complete ionic equation is: [ \text{2 K}^+ (aq) + \text{2 Cl}^- (aq) + \text{Pb}^{2+} (aq) + \text{2 NO}_3^- (aq) \rightarrow \text{2 K}^+ (aq) + \text{2 NO}_3^- (aq) + \text{PbCl}_2 (s) ] The net ionic equation, showing only the species that participate in the formation of the precipitate, is: [ \text{Pb}^{2+} (aq) + \text{2 Cl}^- (aq) \rightarrow \text{PbCl}_2 (s) ]
The net ionic equation for the reaction between Na3PO4(aq) and CaCl2(aq) is: 3 Na+(aq) + 2 PO4^3-(aq) + 3 Ca^2+(aq) + 6 Cl-(aq) → 6 Na+(aq) + 2 Ca3(PO4)2(s) This equation shows the formation of solid calcium phosphate when sodium phosphate and calcium chloride are mixed.
The balanced chemical equation for the reaction is BaCl2(aq) + 2 NaF(aq) → BaF2(s) + 2 NaCl(aq)
The spectator ion is NO3- from Ba(NO3)2, as it remains unchanged throughout the reaction and does not participate in forming the precipitate of Ba3(PO4)2.
The ionic equation is 2K+(aq) + 2OH-(aq) + Co^2(aq) + 2Br^-(aq) ==> 2K+(aq) + 2Br-(aq) + Co(OH)2(s)net ionic equation is Co2+(aq) + 2OH-(aq) ==> Co(OH)2(s)So spectators are K+ and Br- ions.
Mg(NO3)2(aq) + H2SO4(aq) ==> MgSO4(aq) + 2HNO3(aq) Complete molecular equationTotal ionic equation:Mg^2+(aq) + 2NO3^-(aq) + 2H^+(aq) + SO4^2-(aq) => Mg^2+(aq) + SO4^2-(aq) + 2H^+(aq) + 2NO3^-(aq)RESULT - NO REACTION
Ammonium chloride is NH4ClCalcium hydroxide is Ca(OH)2Combining aqueous solutions of each gives the following chemical reaction:2NH4Cl (aq) + Ca(OH)2 (aq) ==> 2NH4OH (aq) + CaCl2 (aq) ==> 2NH3(g) + 2H2O(l) + CaCl2 (aq)
When aqueous solutions of silver(I) sulfate (Ag₂SO₄) and potassium sulfide (K₂S) are combined, a precipitation reaction occurs, forming silver sulfide (Ag₂S) as a solid. The ionic equation for this reaction is: [ 2 \text{Ag}^+ (aq) + \text{S}^{2-} (aq) \rightarrow \text{Ag}_2\text{S} (s) ] In this equation, the potassium ions (K⁺) and sulfate ions (SO₄²⁻) are spectator ions and do not participate in the formation of the precipitate.
The precipitation reaction between potassium hydroxide (KOH) and nickel(II) bromide (NiBr2) can be represented by the following equation: 2 KOH(aq) + NiBr2(aq) → Ni(OH)2(s) + 2 KBr(aq)
The net ionic equation for the reaction between Ba(OH)2 and Na2SO4 is Ba^2+(aq) + SO4^2-(aq) -> BaSO4(s) where BaSO4 is a solid precipitate formed by the combination of Ba^2+ and SO4^2- ions. Sodium ions do not participate in the reaction as they remain in the solution as spectator ions.
Cd^2+(aq) + 2Cl^-(aq) +2Na^+(aq) + S^2-(sq) ==> CdS(s) + 2Na^+(aq) + 2Cl^-(aq)The 2Na^+(aq) and the 2 Cl^-(aq) are spectator ions as they appear on both sides of the equation. Thus, the NET reaction is ...Cd^2+(aq) + S^2-(aq) ==> CdS(s)What else was your question. This is classed as a double replacement reaction.
This reaction is:Mg(s) + Pb(CH3COO)2(aq) → Pb(s) + Mg(CH3COO)2(aq)