When two aqueous solutions are mixed, a precipitation reaction may occur if the products formed are insoluble in water. Whether a precipitate forms depends on the solubility of the compounds involved. If a solid product is formed, it is called a precipitate.
The net ionic equation for the reaction between Na3PO4(aq) and CaCl2(aq) is: 3 Na+(aq) + 2 PO4^3-(aq) + 3 Ca^2+(aq) + 6 Cl-(aq) → 6 Na+(aq) + 2 Ca3(PO4)2(s) This equation shows the formation of solid calcium phosphate when sodium phosphate and calcium chloride are mixed.
The spectator ion is NO3- from Ba(NO3)2, as it remains unchanged throughout the reaction and does not participate in forming the precipitate of Ba3(PO4)2.
The ionic equation is 2K+(aq) + 2OH-(aq) + Co^2(aq) + 2Br^-(aq) ==> 2K+(aq) + 2Br-(aq) + Co(OH)2(s)net ionic equation is Co2+(aq) + 2OH-(aq) ==> Co(OH)2(s)So spectators are K+ and Br- ions.
Mg(NO3)2(aq) + H2SO4(aq) ==> MgSO4(aq) + 2HNO3(aq) Complete molecular equationTotal ionic equation:Mg^2+(aq) + 2NO3^-(aq) + 2H^+(aq) + SO4^2-(aq) => Mg^2+(aq) + SO4^2-(aq) + 2H^+(aq) + 2NO3^-(aq)RESULT - NO REACTION
The precipitation reaction between potassium hydroxide (KOH) and nickel(II) bromide (NiBr2) can be represented by the following equation: 2 KOH(aq) + NiBr2(aq) → Ni(OH)2(s) + 2 KBr(aq)
When solutions of KCl and Pb(NO3)2 are mixed, lead(II) chloride (PbCl2) precipitates. The molecular equation is: [ \text{2 KCl (aq) + Pb(NO}_3\text{)}_2\text{ (aq) } \rightarrow \text{ 2 KNO}_3\text{ (aq) + PbCl}_2\text{ (s)} ] The complete ionic equation is: [ \text{2 K}^+ (aq) + \text{2 Cl}^- (aq) + \text{Pb}^{2+} (aq) + \text{2 NO}_3^- (aq) \rightarrow \text{2 K}^+ (aq) + \text{2 NO}_3^- (aq) + \text{PbCl}_2 (s) ] The net ionic equation, showing only the species that participate in the formation of the precipitate, is: [ \text{Pb}^{2+} (aq) + \text{2 Cl}^- (aq) \rightarrow \text{PbCl}_2 (s) ]
The net ionic equation for the reaction between Na3PO4(aq) and CaCl2(aq) is: 3 Na+(aq) + 2 PO4^3-(aq) + 3 Ca^2+(aq) + 6 Cl-(aq) → 6 Na+(aq) + 2 Ca3(PO4)2(s) This equation shows the formation of solid calcium phosphate when sodium phosphate and calcium chloride are mixed.
The balanced chemical equation for the reaction is BaCl2(aq) + 2 NaF(aq) → BaF2(s) + 2 NaCl(aq)
The spectator ion is NO3- from Ba(NO3)2, as it remains unchanged throughout the reaction and does not participate in forming the precipitate of Ba3(PO4)2.
The ionic equation is 2K+(aq) + 2OH-(aq) + Co^2(aq) + 2Br^-(aq) ==> 2K+(aq) + 2Br-(aq) + Co(OH)2(s)net ionic equation is Co2+(aq) + 2OH-(aq) ==> Co(OH)2(s)So spectators are K+ and Br- ions.
Mg(NO3)2(aq) + H2SO4(aq) ==> MgSO4(aq) + 2HNO3(aq) Complete molecular equationTotal ionic equation:Mg^2+(aq) + 2NO3^-(aq) + 2H^+(aq) + SO4^2-(aq) => Mg^2+(aq) + SO4^2-(aq) + 2H^+(aq) + 2NO3^-(aq)RESULT - NO REACTION
When aqueous solutions of silver(I) sulfate (Ag₂SO₄) and potassium sulfide (K₂S) are combined, a precipitation reaction occurs, forming silver sulfide (Ag₂S) as a solid. The ionic equation for this reaction is: [ 2 \text{Ag}^+ (aq) + \text{S}^{2-} (aq) \rightarrow \text{Ag}_2\text{S} (s) ] In this equation, the potassium ions (K⁺) and sulfate ions (SO₄²⁻) are spectator ions and do not participate in the formation of the precipitate.
Ammonium chloride is NH4ClCalcium hydroxide is Ca(OH)2Combining aqueous solutions of each gives the following chemical reaction:2NH4Cl (aq) + Ca(OH)2 (aq) ==> 2NH4OH (aq) + CaCl2 (aq) ==> 2NH3(g) + 2H2O(l) + CaCl2 (aq)
The precipitation reaction between potassium hydroxide (KOH) and nickel(II) bromide (NiBr2) can be represented by the following equation: 2 KOH(aq) + NiBr2(aq) → Ni(OH)2(s) + 2 KBr(aq)
The net ionic equation for the reaction between Ba(OH)2 and Na2SO4 is Ba^2+(aq) + SO4^2-(aq) -> BaSO4(s) where BaSO4 is a solid precipitate formed by the combination of Ba^2+ and SO4^2- ions. Sodium ions do not participate in the reaction as they remain in the solution as spectator ions.
Cd^2+(aq) + 2Cl^-(aq) +2Na^+(aq) + S^2-(sq) ==> CdS(s) + 2Na^+(aq) + 2Cl^-(aq)The 2Na^+(aq) and the 2 Cl^-(aq) are spectator ions as they appear on both sides of the equation. Thus, the NET reaction is ...Cd^2+(aq) + S^2-(aq) ==> CdS(s)What else was your question. This is classed as a double replacement reaction.
This reaction is:Mg(s) + Pb(CH3COO)2(aq) → Pb(s) + Mg(CH3COO)2(aq)