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When two aqueous solutions are mixed, a precipitation reaction may occur if the products formed are insoluble in water. Whether a precipitate forms depends on the solubility of the compounds involved. If a solid product is formed, it is called a precipitate.

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When solutions of KCl and Pb(NO3)2 are mixed a precipitate forms. Write the molecular ionic and net ionic equations for this reaction.?

When solutions of KCl and Pb(NO3)2 are mixed, lead(II) chloride (PbCl2) precipitates. The molecular equation is: [ \text{2 KCl (aq) + Pb(NO}_3\text{)}_2\text{ (aq) } \rightarrow \text{ 2 KNO}_3\text{ (aq) + PbCl}_2\text{ (s)} ] The complete ionic equation is: [ \text{2 K}^+ (aq) + \text{2 Cl}^- (aq) + \text{Pb}^{2+} (aq) + \text{2 NO}_3^- (aq) \rightarrow \text{2 K}^+ (aq) + \text{2 NO}_3^- (aq) + \text{PbCl}_2 (s) ] The net ionic equation, showing only the species that participate in the formation of the precipitate, is: [ \text{Pb}^{2+} (aq) + \text{2 Cl}^- (aq) \rightarrow \text{PbCl}_2 (s) ]


What net ionic equation describes the reaction when these solutions are mixed Na3PO4 (aq) plus CaCl2(aq) and rarr?

The net ionic equation for the reaction between Na3PO4(aq) and CaCl2(aq) is: 3 Na+(aq) + 2 PO4^3-(aq) + 3 Ca^2+(aq) + 6 Cl-(aq) → 6 Na+(aq) + 2 Ca3(PO4)2(s) This equation shows the formation of solid calcium phosphate when sodium phosphate and calcium chloride are mixed.


How would you write this chemical equation Aqueous solutions of barium chloride and sodium fluoride are mixed to form a precipitate of barium fluoride and aqueous sodium chloride?

The balanced chemical equation for the reaction is BaCl2(aq) + 2 NaF(aq) → BaF2(s) + 2 NaCl(aq)


Which is a spectator ion in the reaction between Ba(NO3)2(aq) and (NH4)3PO4(aq)?

The spectator ion is NO3- from Ba(NO3)2, as it remains unchanged throughout the reaction and does not participate in forming the precipitate of Ba3(PO4)2.


Which is a spectator ion in the reaction between KOH and CoBr2?

The ionic equation is 2K+(aq) + 2OH-(aq) + Co^2(aq) + 2Br^-(aq) ==> 2K+(aq) + 2Br-(aq) + Co(OH)2(s)net ionic equation is Co2+(aq) + 2OH-(aq) ==> Co(OH)2(s)So spectators are K+ and Br- ions.


What is the total ionic equation for magnesium nitrate and sulfuric acid?

Mg(NO3)2(aq) + H2SO4(aq) ==> MgSO4(aq) + 2HNO3(aq) Complete molecular equationTotal ionic equation:Mg^2+(aq) + 2NO3^-(aq) + 2H^+(aq) + SO4^2-(aq) => Mg^2+(aq) + SO4^2-(aq) + 2H^+(aq) + 2NO3^-(aq)RESULT - NO REACTION


Aqueous ammonium chloride and aqueous calcium hydroxide?

Ammonium chloride is NH4ClCalcium hydroxide is Ca(OH)2Combining aqueous solutions of each gives the following chemical reaction:2NH4Cl (aq) + Ca(OH)2 (aq) ==> 2NH4OH (aq) + CaCl2 (aq) ==> 2NH3(g) + 2H2O(l) + CaCl2 (aq)


What is the ionic equation when aqueous solutions of silver(I) sulfate and potassium sulfide are combined?

When aqueous solutions of silver(I) sulfate (Ag₂SO₄) and potassium sulfide (K₂S) are combined, a precipitation reaction occurs, forming silver sulfide (Ag₂S) as a solid. The ionic equation for this reaction is: [ 2 \text{Ag}^+ (aq) + \text{S}^{2-} (aq) \rightarrow \text{Ag}_2\text{S} (s) ] In this equation, the potassium ions (K⁺) and sulfate ions (SO₄²⁻) are spectator ions and do not participate in the formation of the precipitate.


What is the equation for precipitation reaction that occurs when solutions of potassium hydroxide and nickel bromide are mixed?

The precipitation reaction between potassium hydroxide (KOH) and nickel(II) bromide (NiBr2) can be represented by the following equation: 2 KOH(aq) + NiBr2(aq) → Ni(OH)2(s) + 2 KBr(aq)


What is the net ionic equation for baoh2 plus na2so4?

The net ionic equation for the reaction between Ba(OH)2 and Na2SO4 is Ba^2+(aq) + SO4^2-(aq) -> BaSO4(s) where BaSO4 is a solid precipitate formed by the combination of Ba^2+ and SO4^2- ions. Sodium ions do not participate in the reaction as they remain in the solution as spectator ions.


Cd2 plus (aq) plus 2Cl-(aq) plus 2Na plus (aq) plus S2-(aq) CdS(s) plus 2Na plus (aq) plus 2Cl-(aq)?

Cd^2+(aq) + 2Cl^-(aq) +2Na^+(aq) + S^2-(sq) ==> CdS(s) + 2Na^+(aq) + 2Cl^-(aq)The 2Na^+(aq) and the 2 Cl^-(aq) are spectator ions as they appear on both sides of the equation. Thus, the NET reaction is ...Cd^2+(aq) + S^2-(aq) ==> CdS(s)What else was your question. This is classed as a double replacement reaction.


What does lead acetate and magnesium make?

This reaction is:Mg(s) + Pb(CH3COO)2(aq) → Pb(s) + Mg(CH3COO)2(aq)