Na2S2O3 does react with AgNO3, it is a reaction widely used in non-digital Photography. The reaction is:
2AgNO3 + Na2S2O3 = Ag2S2o3 + 2 NaNo3
If hypo is taken in a limited amount, then this happens. The Ag thiosulphate thus formed goes through a change of colour (termed as 'play of colour').
Ag2S2O3 (white) --> yellow --> orange --> brown --> black (AgS ppt).
But if hypo is taken in excess amount, then a complex [Ag(S2O3)2]3- , it is readily dissolved in water.
Yes, but your formula for copper II nitrate is incorrect. It should be Cu(NO3)2. The correct equation is Cu(NO3)2 + 2HCl --> CuCl2 + 2HNO3.
first we calculate the molecular weight M.W=158.11 mass of Na2S2O3=M.W*concentration*volume(in litter) for a concentration of 0.001 mass of Na2S2O3=158.11*0.001*1=0.15811 g so we use this mass and continue the volume to be 1 L
The blank titration requires more sodium thiosulfate (Na2S2O3) because it compensates for any residual iodine in the reaction mixture that didn't react with the analyte. This residual iodine can interfere with the accuracy of the titration results, so more Na2S2O3 is needed to completely neutralize it.
The anion in CuCl2 is chloride (Cl-).
Na2S2O3(aq) + 2HCL(aq) => 2NaCl(aq) + S(s) + SO2(g) + H2O(l)
CuCl2 + Na2SO4 --> CuSO4 + 2NaCl
Potassium iodide (KI) does not react with sodium thiosulfate (Na2S2O3) because the two compounds belong to different chemical families and do not have a significant affinity for each other. KI is a salt of potassium and iodine, while sodium thiosulfate is a salt of sodium and thiosulfate ions. The lack of reactivity between KI and Na2S2O3 is due to their stable chemical structures and the absence of driving forces for a reaction to occur.
To prepare a 0.1N Na2S2O3 solution, dissolve 24.98 grams of Na2S2O3·5H2O (sodium thiosulfate pentahydrate) in distilled water and dilute to 1 liter in a volumetric flask. This will give you a 0.1N (normal) solution of Na2S2O3.
Yes, but your formula for copper II nitrate is incorrect. It should be Cu(NO3)2. The correct equation is Cu(NO3)2 + 2HCl --> CuCl2 + 2HNO3.
first we calculate the molecular weight M.W=158.11 mass of Na2S2O3=M.W*concentration*volume(in litter) for a concentration of 0.001 mass of Na2S2O3=158.11*0.001*1=0.15811 g so we use this mass and continue the volume to be 1 L
The blank titration requires more sodium thiosulfate (Na2S2O3) because it compensates for any residual iodine in the reaction mixture that didn't react with the analyte. This residual iodine can interfere with the accuracy of the titration results, so more Na2S2O3 is needed to completely neutralize it.
The anion in CuCl2 is chloride (Cl-).
Na2S2O3(aq) + 2HCL(aq) => 2NaCl(aq) + S(s) + SO2(g) + H2O(l)
Yes, copper does react with hydrochloric acid to form copper chloride and hydrogen gas. The reaction can be represented by the equation: Cu(s) + 2HCl(aq) → CuCl2(aq) + H2(g).
Na2S2O3
Sodium thiosulfate
Copper does not react with hydrochloric acid (HCl) because it is less reactive than hydrogen. It forms a passive layer of copper chloride (CuCl2) on its surface, which protects the copper underneath from further reaction with the acid.