Yes.
The alpha protons on the methyl group will be deprotonated and react with halides and eventually form a trihaloform group or (-C-CX3). The Trihalofrom is explelled when a OH group attacks the carbonyl carbon. This forms the trihaloform carbanion of the carboxylic acid. The anion takes a hydrogen from the acid to form the haloform and a carboxylic salt
amino acid
If the ∆H is positive and the ∆S is positive, then the reaction is entropy driven. If the ∆H is negative and the ∆S is negative, then the reaction is enthalpy driven. If ∆H is positive and ∆S is negative, then the reaction is driven by neither of these. If ∆H is negative and ∆S is positive, then the reaction is driven by both of these.
No because vanillin is phenolic aldehyde (only acetaldehyde give idoform among all ketones)
Heat (300º?) styrene oxide in a closed system, you will obtain a mixture of styrene oxide and phenyl acetaldehyde. IIRC you can heat at reflux S.O. and some kind of silica catalyst with a solvent and obtain that same product.
Electron density on oxygen in phenoxide ion is decreased due to resonance. The oxygen rather acquire a positive charge. Therefore phenol does not give protonation readily
amino acid
If the ∆H is positive and the ∆S is positive, then the reaction is entropy driven. If the ∆H is negative and the ∆S is negative, then the reaction is enthalpy driven. If ∆H is positive and ∆S is negative, then the reaction is driven by neither of these. If ∆H is negative and ∆S is positive, then the reaction is driven by both of these.
Change in enthalpy value for a chemical reaction is positive is because,there loose of electron(s) in the reaction, and that will change the enthalpy of that particular element from negetive,neutral to positive.
No because vanillin is phenolic aldehyde (only acetaldehyde give idoform among all ketones)
Negative: they bite... not only that but they may also give some allergic reaction to one's body after they attack...
No, because phenylalanine does not react with the nitric acid in this test.
Acetaldehyde can be converted to butane-1,3-diol in a two-step process. First, acetaldehyde is reduced to 1,3-propanediol using a reducing agent like sodium borohydride. Then, 1,3-propanediol can be dehydrated to form butane-1,3-diol using an acid catalyst, such as sulfuric acid.
Heat (300º?) styrene oxide in a closed system, you will obtain a mixture of styrene oxide and phenyl acetaldehyde. IIRC you can heat at reflux S.O. and some kind of silica catalyst with a solvent and obtain that same product.
It means the person is wanting to give reaction to the weather. He/She wants to give reaction about the day.
Electron density on oxygen in phenoxide ion is decreased due to resonance. The oxygen rather acquire a positive charge. Therefore phenol does not give protonation readily
all reducing sugars - monosaccharides like glucose and a few non-reducing disaccharides like maltose
Yes it give positive result