Yes, use the Hardy-Weinburg equilibrium equation.
Hardy Weinburg
No allele can give an advantage
The Hardy-Weinberg principle disproved the idea that allele frequencies in a population remain constant over time without the influence of evolutionary forces. It established that, in a large, randomly mating population with no mutations, migration, or selection, allele frequencies will remain stable generation after generation. This principle provided a mathematical framework for understanding how evolutionary processes can lead to changes in genetic variation within populations.
Hardy Diagnostics's population is 180.
If you assume hardy-weinburg equilibrium, then:let B = frequency of black allele (dominant)b = frequency of white allele (recessive)BB (or B^2) = frequency of homozygous black sheep2Bb = frequency of heterozygous black sheepbb (or b^2) = frequency of white sheepSince 9% of the sheep are white, the frequency of white sheep is 0.09, or bb = 0.09, so b=.3, which means B = 1-b = 1-.3 = 0.7You should check to make sure that the hardy-weinburg assumption holds:BB = 0.492Bb = 0.42And BB + 2Bb = 0.91, which is the frequency of black sheep. ?The hardy-weinburg assumption is valid!
Chorlton-cum-Hardy's population is 13,512.
The Hardy-Weinberg principle is a bit like the "Punnett square for populations". A Punnett square can predict the probability of offspring's genotype based on parents' genotype, or the offsprings' genotype can be used to reveal the parents' genotype. The Hardy-Weinberg principle can be used to calculate the frequency of particular alleles based on frequency diseases. This principle can determine useful but difficult-to-measure facts about a population.
According to census.gov, the 2007 population estimate of Hardy County, West Virginia, is 12,669.
A large population residing on an isolated island is more likely to reach Hardy-Weinberg equilibrium.
rarely
Hardy-Weinberg equilibrium