it has 32 kB of internal memory
ATmega 168 was a flash program memory from ATMEL; now replaced by ATmega 168PA.
RAM and the memory cache
Different microprocessor can address different amounts of memory. The motherboard design should allow for maximising the physical memory to what the microprocessor can address
An 80286 has a 24 bit address bus. As such, it can address 224, or 16,777,216, or 16 MB of memory.
A memory address is a specific location in a computer's memory where data is stored. Memory addressability refers to the maximum amount of memory that a computer system can access and use. In other words, memory addressability is the range of memory addresses that a computer can access, while a memory address is a specific location within that range.
Probably damaged memory. If computer memory is damaged the memory is marked as bad by controller on the chip. A lower amount of memory is reported to the operating system. Also Windows XP will only address 4gb of ram without using a physical address extension. More than this is ignored.
You will need to know what software you will be using to operate your system to help determine the amount of memory needed.
To determine the contents of a memory location, you typically need to access the memory address using a programming language or debugging tool. For example, in languages like C or C++, you can use pointers to reference the specific memory address and retrieve its value. In a debugging environment, you can view memory contents directly by specifying the address. The contents will depend on what data has been stored at that location, which could be a variable, an array element, or other data types.
32 bit processor can access 4294967296 bit memory adderss.
You can determine the amount of memory a device driver allocates for itself and its data by using the MEM command with the \M filename option.A+ Guide to software fourth edition page 311
To determine the number of address lines required for 1 GB of memory, we can use the formula (2^n = \text{Memory Size}), where (n) is the number of address lines. Since 1 GB equals (2^{30}) bytes, we need (30) address lines to uniquely address each byte in 1 GB of memory. Therefore, (30) address lines are required for 1 GB.
A 16-bit address bus can address (2^{16}) memory locations, which equals 65,536 locations. Since each location typically represents one byte, the total memory is 65,536 bytes. To convert this into kilobytes (K), divide by 1,024, resulting in 64 K. Thus, a 16-bit address bus can address a total of 64 Kbytes of memory.